将类添加到Django label_tag（）输出 [英] Add class to Django label_tag() output

问题描述

我需要一些方法来为表单字段的label_tag（）方法的输出添加一个类属性。

我看到有能力传递一个attrs字典，我已经在shell中进行了测试，我可以这样做：

 表单中的字段：
 print field.label_tag（attrs {'class'：'Foo'}）
  

我将在我的输出中看到class ='Foo'，但是我没有看到从模板中添加attrs参数的方法 - 实际上，模板是专门设计的，不是吗？

我的表单定义有一种方法来定义要在标签中显示的类？

在表单中，我可以执行以下操作来输入一个类

  self.fields ['some_field']。widget.attrs ['class'] ='Foo'
  

我只需要输出类。

解决方案

A 自定义模板标签似乎是解决方案。自定义过滤器也可以做，尽管它可以不太优雅。但是，在这两种情况下，您都需要回到自定义表单渲染。

如果这是一个非常重要的任务，我将创建一个Mixin，让我用标签类和表单渲染方法使用这些类来注释表单域。以下代码的作用如下：

  {{form.as_table_with_label_classes}} 
  / pre> 
 
 
但我想问一下;你真的需要一个类标签标签吗？我的意思是HTML设计。在这里添加一个类是绝对必要的不能用一些CSS来解决，如：
  encapsulationulating_selector label {
 some-attr：some-value; 
} 
  
我有时使用 jQuery 对于这种情况，其中;如果它不起作用，它将改善页面，但如果不则不会是灾难。并保持HTML源尽可能精简。
 
I need some way to add a class attribute to the output of the label_tag() method for a forms field. 

I see that there is the ability to pass in an attrs dictionary and I have tested it in the shell and I can do something like:
for field in form:
    print field.label_tag(attrs{'class':'Foo'})
I will see the class='Foo' in my output, but I don't see a way to add an attrs argument from the template - in fact, templates are designed specifically against that, no?

Is there a way in my form definition to define the class to be displayed in the label?

In the form, I can do the following to give the inputs a class
self.fields['some_field'].widget.attrs['class'] = 'Foo'
I just need to have it output the class for the  as well.
解决方案
A custom template tag seems to be the solution. A custom filter would also do, although it can be less elegant. But you would need to fall back to custom form rendering in both cases.

If this is a task of high importance; I'd create a Mixin that allows me to annotate the form fields with label classes and supplies form rendering methods using those classes. So that the following code works:
{{ form.as_table_with_label_classes }}
But I'd like to ask; Do you really need a class on the label tag? I mean HTML design-wise. It is absolutely necessary to add a class in there? Couldn't it be solved with some CSS like:
encapsulating_selector label {
    some-attr: some-value;
}
I sometimes use jQuery for such cases where; it will improve the page if it works, but it won't be a disaster if it doesn't. And keep the HTML source as lean as possible.

                        
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