django请求在模板中 [英] django request in template
本文介绍了django请求在模板中的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我启用了django请求处理器
I've enabled the django request processor
TEMPLATE_PROCESSORS = (
"django.core.context_processors.auth",
"django.core.context_processors.debug",
"django.core.context_processors.i18n",
"django.core.context_processors.media",
"django.core.context_processors.request",
)
仍然我不必要求变量在模板中可用。
我必须手动传递它。使用django 1.0.2
在网络上的每个地方似乎只是关于启用的请求处理器..
Still i don't have to request variable available in templates. I've to manually pass it. Using django 1.0.2 Everywhere on web it seems it's only about enabled request processor..
另外我正在使用RequestContext:
Also i am using RequestContext as :
return render_to_response(
'profile.html',
{
'persons':Person.objects.all(),
'person':Person.objects.get(id=id),
'request':request,
},
context_instance=RequestContext(request)
)
没有运气
ohh darn
新的名字是 TEMPLATE_CONTEXT_PROCESSORS
ohh darn
the new name for that is TEMPLATE_CONTEXT_PROCESSORS
推荐答案
settings.py:
settings.py:
TEMPLATE_CONTEXT_PROCESSORS = (
# ...
'django.core.context_processors.request',
# ...
)
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