如何在django管理员更改列表视图页面中添加一个按钮 [英] How can I add a button into django admin change list view page

问题描述

我想在模型中的列表视图中的添加按钮旁边添加一个按钮，然后创建一个视图函数，我将在此处执行我的内容，然后将用户重定向到列表视图。

I would like to add a button next to "add" button in list view in model for my model and then create a view function where I will do my stuff and then redirect user back to list view.

我已经检查过如何重载管理模板，但是我仍然不知道，我应该把我的视图功能放在哪里，我该怎么做，我该怎么把这个视图注册到管理URL 。

I've checked how to overload admin template, but I still dont know, where should I put my view function where I will do my stuff, and how can I register that view into admin urls.

还有关于安全性的问题。我想在管理员内部执行该操作，所以如果你没有登录，你不能使用它。

There is also question about security. I would like to have that action inside admin, so if u r not logged in, u cannot use it.

我发现这个，但我不知道这是正确的方法： http：/ /www.stavros.io/posts/how-to-extend-the-django-admin-site-with-custom/

I've found this, but I don't know if it's the right way: http://www.stavros.io/posts/how-to-extend-the-django-admin-site-with-custom/

推荐答案

当多个应用程序提供不同版本的相同
资源（模板，静态文件，管理命令，翻译）时，INSTALLED_APPS中首先列出的
应用程序优先。
- 有关INSTALLED_APPS的Django文档

确保您的应用程序在'django.contrib.admin'之前列出在 INSTALLED_APPS 。

Make sure your app is listed before 'django.contrib.admin' in INSTALLED_APPS.

创建一个 change_list.html 模板在以下目录之一：

Create a change_list.html template in one of the following directories:

# Template applies to all change lists.
myproject/myapp/templates/admin/change_list.html      

# Template applies to change lists in myapp.
myproject/myapp/templates/admin/myapp/change_list.html  

# Template applies to change list in myapp and only to the Foo model.
myproject/myapp/templates/admin/myapp/foo/change_list.html  

模板应该自动拾取，但是如果不在上面列出的路径之一，您还可以通过管理模型属性指向：

The template should be picked up automatically, but in case it is not on one of paths listed above, you can also point to it via an admin model attribute:

class MyModelAdmin(admin.ModelAdmin):

    #... 
    change_list_template = "path/to/change_list.html"

您可以在 path / to / your / site-packages / django中查找原始的change_list.html的内容/contrib/admin/templates/admin/change_list.html 。 其他答案还显示了如何格式化模板。 Nikolai Saiko向您展示如何使用'extend'和'super'覆盖相关的部分。摘要：

You can lookup the contents of the original change_list.html it lives in path/to/your/site-packages/django/contrib/admin/templates/admin/change_list.html. The other answer also shows you how to format the template. Nikolai Saiko shows you how to override the relevant parts using 'extends' and 'super'. Summary:

{% extends "admin/change_form.html" %} {% load i18n %} 
{% block object-tools-items %}
    {{ block.super }}
    <li>
        <a class="historylink" href="...">My custom admin page</a>
    </li>
{% endblock %}

我们填写 href =。 ..与网址。管理员的URL名称在命名空间admin中，可以这样查找：

Let's fill href="..." with an url. The admin url names are in the namespace 'admin' and can be looked up like this:

{% url 'admin:custom_view' %}

当您添加一个按钮到change_form.html时，您可能想要传入当前对象ID：

When you are adding a button to change_form.html you maybe want to pass in the current object id:

{% url 'admin:custom_view' original.pk %}

现在创建一个自定义视图。这可以是常规视图（就像您网站上的其他页面）或admin.py中的自定义管理视图。 ModelAdmin上的get_urls方法以与URLconf相同的方式返回要用于该ModelAdmin的URL。因此，您可以按照URL调度程序的说明扩展它们：

Now create a custom view. This can be a regular view (just like other pages on your website) or a custom admin view in admin.py. The get_urls method on a ModelAdmin returns the URLs to be used for that ModelAdmin in the same way as a URLconf. Therefore you can extend them as documented in URL dispatcher:

class MyModelAdmin(admin.ModelAdmin):
    def get_urls(self):
        urls = super(MyModelAdmin, self).get_urls()
        my_urls = patterns('',
            url(r'^my_view/$', self.my_view, name="custom_view")
        )
        return my_urls + urls

    def my_view(self, request):
        # custom view which should return an HttpResponse
        pass

    # In case your template resides in a non-standard location
    change_list_template = "path/to/change_list.html"

阅读有关如何在ModelAdmin中设置视图的权限的文档： https://docs.djangoproject.com/en/1.5/ref/contrib/admin/#django.contrib.admin.ModelAdmin。 get_urls

Read the docs on how to set permissions on a view in ModelAdmin: https://docs.djangoproject.com/en/1.5/ref/contrib/admin/#django.contrib.admin.ModelAdmin.get_urls

你可以保护查看您的视图，并且只允许访问具有员工身份的用户：

You can protect your view and only give access to users with staff status:

from django.contrib.admin.views.decorators import staff_member_required

@staff_member_required
def my_view(request):
    ...

您可能还需要检查 request.user.is_active 并处理非活动用户。

You might also want to check request.user.is_active and handle inactive users.

更新：尽可能少地利用框架和自定义。很多时候，行动可以是一个很好的选择： https：// docs。 djangoproject.com/en/1.5/ref/contrib/admin/actions/

Update: Take advantage of the framework and customise as little as possible. Many times actions can be a good alternative: https://docs.djangoproject.com/en/1.5/ref/contrib/admin/actions/

更新2：我删除了一个JS示例来注入一个按钮客户端。如果需要，请参阅修订版本。

Update 2: I removed a JS example to inject a button client side. If you need it, see the revisions.

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