有一种方法可以在现有的django命令中添加功能? [英] There is a way to add features to an existing django command?

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问题描述

我想在django命令启动之前运行命令。

I want to run a command just before the a django command is started.

例如:

$ python manage.py runserver
Validating models...

0 errors found
Django version 1.3, using settings 'creat1va.settings'
Development server is running at http://127.0.0.1:8000/
Quit the server with CONTROL-C.
(started some command in the background)
[10/Jul/2011 21:50:26] "GET / HTTP/1.1" 200 1611
[10/Jul/2011 21:50:26] "GET /assets/css/master.css HTTP/1.1" 404 1783
[10/Jul/2011 21:50:26] "GET /assets/images/misc/logo.png HTTP/1.1" 404 1801
[10/Jul/2011 21:50:26] "GET /assets/images/icons/bo.gif HTTP/1.1" 404 1798
[10/Jul/2011 21:50:28] (My background process) "Some nice Feedback"

主要的想法是开始一个背景处理并输出日志记录。

The main idea is to start a background process, and output the logging.

有没有办法实现这个,而不是黑客的django源?

Is there a way to achieve this, without hacking the django sources?

推荐答案

只要知道你可以轻松地覆盖命令,使用同一个命令的应用程序。

Just realize that you can override the commands just easily as making an app with a command with the same name.

所以我创建一个应用程序并创建与runserver名称相同的文件,稍后再扩展runserver基类以在运行之前添加一个新功能。

So I create an app and create a file with the same name as runserver, and later on that extend the runserver base class to add a new feature before it runs.

例如,我想运行命令$ c ompass手表,在runserver启动之前,并保持运行在runserver执行。

For example, I want to run the command $ compass watch, just before runserver starts and keep it running along runserver execution.

"""
Start $compass watch, command when you do $python manage.py runserver

file: main/management/commands/runserver.py

Add ´main´ app to the last of the installed apps
"""

from optparse import make_option
import os
import subprocess

from django.core.management.base import BaseCommand, CommandError
from django.core.management.commands.runserver import BaseRunserverCommand
from django.conf import settings

class Command(BaseRunserverCommand):
    option_list = BaseRunserverCommand.option_list + (
        make_option('--adminmedia', dest='admin_media_path', default='',
            help='Specifies the directory from which to serve admin media.'),
        make_option('--watch', dest='compass_project_path', default=settings.MEDIA_ROOT,
            help='Specifies the project directory for compass.'),
    )

    def inner_run(self, *args, **options):
        self.compass_project_path = options.get('compass_project_path', settings.MEDIA_ROOT)

        self.stdout.write("Starting the compass watch command for %r\n" % self.compass_project_path)
        self.compass_pid = subprocess.Popen(["compass watch %s" % self.compass_project_path],
            shell=True,
            stdin=subprocess.PIPE,
            stdout=self.stdout,
            stderr=self.stderr)
        self.stdout.write("Compas watch process on %r\n" % self.compass_pid.pid)

        super(Command, self).inner_run(*args, **options)

这个工作很好。

查看 https://docs.djangoproject.com/en/dev/ howto / custom-management-commands / 进一步了解ls about django命令

Look at https://docs.djangoproject.com/en/dev/howto/custom-management-commands/ for more details about django commands

希望有人找到有用的

这篇关于有一种方法可以在现有的django命令中添加功能?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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