django形式：将参数从view.py传递给表单发出错误 [英] django form: Passing parameter from view.py to forms gives out error

问题描述

新手问题：
我需要从一个form.py中的一个表单中接受一个参数，但是它给了我很多麻烦。在视图中，我创建了一个包含以下代码片段的方法：

  def scan_page（request）：
 myClient = request.user .get_profile（）。client 
 form = WirelessScanForm（client = myClient）＃pass参数到
  

并在forms.py中定义了以下格式：

  class WirelessScanForm（forms.ModelForm）：
 time = forms.DateTimeField（label =Schedule Time，widget = AdminSplitDateTime（））
 
 def __init __（self，* args，** kwargs）：
 myClient = kwargs.pop （client）＃client是从views.py 
 super（WirelessScanForm，self）传递的参数。_ init __（* args，** kwargs）
 prob = forms.ChoiceField（label =Sniffer ，choices = [x.sniffer.plug_ip for x in Sniffer.objects.filter（client = myClient）]）
  

但是django不断给我错误说： TemplateSyntaxError：在渲染时捕获NameError：name'myClient'不是def in （查询中发生此错误）

我恐怕这里会有一些愚蠢的错误，但是我无法真正弄清楚为什么。请帮助，谢谢。

解决方案

假设我正确地更正了格式，你有一个缩进问题： prob 在 __ init __ 之外，因此无法访问本地 myClient 变量但是，如果你把它带入方法，它仍然不会工作，因为还有另外两个问题：首先，简单地将一个字段赋给一个变量，赢得'将它放在表格上;其次，选项属性需要一个2元组列表，而不仅仅是平面列表。您需要的是：

  def __init __（self，* args，** kwargs）：
 myClient = kwargs .pop（client）＃client是从views.py 
 super（WirelessScanForm，self）传递的参数.__ init __（* args，** kwargs）
 self.fields ['prob'] =在Sniffer.objects.filter（client = myClient）中的x的forms.ChoiceField（label =Sniffer，choices = [（x.plug_ip，x.MY_DESCRIPTIVE_FIELD）]）
  pre> 
 
 
显然将 MY_DESCRIPTIVE_FIELD 替换为要在选项中显示的实际字段。
 
Newbie question:
I need to accept a parameter in a form from a method in views.py but it gave me troubles. In the view I created a method with following snippet:
def scan_page(request):
    myClient = request.user.get_profile().client
    form = WirelessScanForm(client = myClient)   # pass parameter to the form
and in the forms.py I defined the following form:
class WirelessScanForm(forms.ModelForm):
    time = forms.DateTimeField(label="Schedule Time", widget=AdminSplitDateTime())

    def __init__(self,*args,**kwargs):
        myClient = kwargs.pop("client")     # client is the parameter passed from views.py
        super(WirelessScanForm, self).__init__(*args,**kwargs)
        prob = forms.ChoiceField(label="Sniffer", choices=[ x.sniffer.plug_ip for x in Sniffer.objects.filter(client = myClient) ])
But django keeps giving me error saying: TemplateSyntaxError: Caught NameError while rendering: name 'myClient' is not defined(This error happens in the query)

I'm afraid it would be something stupid missing here, but I cannot really figure out why. Please help, thanks.
解决方案
Assuming I've corrected your formatting properly, you have an indentation issue: prob is outside __init__, so doesn't have access to the local myClient variable.

However if you bring it inside the method, it still won't work, as there are two other issues: first, simply assigning a field to a variable won't set it on the form; and second, the choices attribute needs a list of 2-tuples, not just a flat list. What you need is this:
def __init__(self,*args,**kwargs):
    myClient = kwargs.pop("client")     # client is the parameter passed from views.py
    super(WirelessScanForm, self).__init__(*args,**kwargs)
    self.fields['prob'] = forms.ChoiceField(label="Sniffer", choices=[(x.plug_ip, x.MY_DESCRIPTIVE_FIELD) for x in Sniffer.objects.filter(client = myClient)])
Obviously replace MY_DESCRIPTIVE_FIELD with the actual field you want displayed in the choices.

                        
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