Django：从Inline模型管理员访问父实例 [英] Django: access the parent instance from the Inline model admin

问题描述

如何从内联模型管理员访问父实例？

How can I access the parent instance from the inline model admin?

我的目标是覆盖 has_add_permission 函数基于父实例的状态。如果父母的状态不同于1，我不想允许添加一个小孩。

My goal is to override the has_add_permission function based on the status of the parent instance. I don't want to allow to add a child if the status of the parent is different than 1.

class ChildInline(admin.TabularInline):
    model = Child
    form = ChildForm

    fields = (
        ...
    )
    extra = 0

    def has_add_permission(self, request):
        # Return True only if the parent has status == 1
        # How to get to the parent instance?
        #return True

class ParentAdmin(admin.ModelAdmin):
    inlines = [ChildInline,]

推荐答案

使用Django的Request对象（您可以访问）来检索 request.path_info ，然后检索来自 解决方案中的参数的PK c $ c> 匹配。示例：

Use Django's Request object (which you have access to) to retrieve the request.path_info, then retrieve the PK from the args in the resolve match. Example:

from django.contrib import admin
from django.core.urlresolvers import resolve
from app.models import YourParentModel, YourInlineModel


class YourInlineModelInline(admin.StackedInline):
    model = YourInlineModel

    def get_parent_object_from_request(self, request):
        """
        Returns the parent object from the request or None.

        Note that this only works for Inlines, because the `parent_model`
        is not available in the regular admin.ModelAdmin as an attribute.
        """
        resolved = resolve(request.path_info)
        if resolved.args:
            return self.parent_model.objects.get(pk=resolved.args[0])
        return None

    def has_add_permission(self, request):
        parent = self.get_parent_object_from_request(request)

        # Validate that the parent status is active (1)
        if parent:
            return parent.status == 1

        # No parent - return original has_add_permission() check
        return super(YourInlineModelInline, self).has_add_permission(request)


@admin.register(YourParentModel)
class YourParentModelAdmin(admin.ModelAdmin):
    inlines = [YourInlineModelInline]

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