在Django网址中传递一个id [英] Passing an id in Django url

问题描述

我想通过 userid 从django url到我的视图

I want to pass userid from django url to my view

这是我在Django中写的模板

Here is what I have written in Django template

<a href ={% url 'user_details' x.id  %} class='btn btn-primary' style="float: right;" >Know More</a></div>

为了处理这个URL，我已经写了像

To handle this url I have written Url like

url(r'^User/(\d{userid})/$', 'search.views.user_detail',name='user_details'),     

但是我收到一个错误，即

But I am getting an error i.e

NoReverseMatch at /search/

Reverse for ''user_details'' with arguments '(2L,)' and keyword arguments '{}' not found.

请帮助我在这里我可能做错了。

Please help me out What might I am doing wrong here .

推荐答案

无报价''

<a href ={% url user_details x.id  %} class='btn btn-primary' style="float: right;" >
    Know More
</a>

另一个您的网址

url(r'^User/(?P<userid>\d+)/$', 'search.views.user_detail', name='user_details'), 

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