Python获取文件名并更改&保存在变量中 [英] Python get file name and change & save it in variable

问题描述

我正在关注需要一个最小的Django文件上传示例。在view.py中有

I am following Need a minimal Django file upload example. in view.py there is

newdoc = Document(docfile = request.FILES['docfile'])
newdoc.save

让我说上传文件 xyz.csv 将newdoc或docfile作为

Let say I upload the file xyz.csv which make newdoc or docfile as

newdoc = xyz.csv 或 docfile = xyz.csv

我想做：

changedoc = xyz.txt

ie我想删除扩展名，并给它 .txt extension

i.e. I want to remove the extension and give it .txt extension

我该怎么玩？
我只需要提取名称，而不是文件本身。

How I can play with it? I just need to extract the name only not the file itself.

推荐答案

从 request.FILES ['docfile']。name ，使用 os.path.splitext（）获取不带扩展名的文件名：

Read the file name from request.FILES['docfile'].name, use os.path.splitext() to get the file name without extension:

docfile = request.FILES['docfile']
filename = os.path.splitext(docfile.name)[0]
newfilename = 'ok_%s.txt' % filename

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