如何调用django功能按钮点击 [英] how to call a django function on button click
问题描述
我正在尝试编写一个Django应用程序，当我点击一个按钮时，我可以调用视图功能。
在我的模板中，我有一个链接按钮如下所示，当您点击到另一个网页。
< a target =_ blankclass =btn btn-info pull-righthref ={{column_3_item.link_for_item}}>检查出< / a>
当点击按钮时，我还要调用Django视图功能（以及重新直接到目标网站）。视图功能是增加存储按钮被点击次数的数据库中的值。
任何人都可以帮助我如何实现这一点。 p>
编辑： -
抱歉的困惑。 column_3_item.link_for_item是指向外部网站的链接（例如：www.google.com）。现在当该按钮被点击时，它打开一个新的窗口，它需要谷歌网站。我想要做的是在点击按钮更新数据库而不刷新页面的同时调用django视图函数。
谢谢
这里是一个纯JavaScript，简约的方法。我使用JQuery，但您可以使用任何库（甚至没有图书馆）。
< html>
< head>
< title>示例< / title>
< script src =http://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js>< / script>
< script>
函数call_counter（url，pk）{
window.open（url）;
$ .get（'YOUR_VIEW_HERE /'+ pk +'/'，function（data）{
alert（counter updated！）;
}）;
}
< / script>
< / head>
< body>
< button onclick =call_counter（'http://www.google.com'，12345）;>
我更新对象12345
< / button>
< button onclick =call_counter（'http://www.yahoo.com'，999）;>
我更新对象999
< / button>
< / body>
< / html>
替代方法 / p>
而不是放置JavaScript代码，您可以通过以下方式更改链接：
< a target =_ blank
class =btn btn-info pull-right
href ={％url YOUR_VIEW column_3_item.pk％} /？next = {{column_3_item .link_for_item |进行urlencode： ''}}>
Check out Out
< / a>
和您的 views.py ：
def YOUR_VIEW_DEF（request，pk）：
YOUR_OBJECT.objects.filter（pk = pk）.update（views = F（'views'）+ 1）
return HttpResponseRedirect（request.GET.get（'next'）））
I am trying to write a Django application and i am stuck at how i can call a view function when a button is clicked.
In my template, i have a link button as below when clicked takes you to a different webpage.
<a target="_blank" class="btn btn-info pull-right" href="{{ column_3_item.link_for_item }}">Check It Out</a>
When the button is clicked, i want to call a Django view function also (along with re-direct to a target website). The view function is to increment the value in the database which stores the number of times the button is clicked.
Could anyone please help me how i can achieve this.
Edit :-
sorry for the confusion. the column_3_item.link_for_item is a link to an external website (example:- www.google.com). Right now when that button is clicked, it opens a new window which takes to google website. what i would like to do is to call a django view function also when the button is clicked which updates the database without refreshing the page.
Thanks
here is a pure-javascript, minimalistic approach. I use JQuery but you can use any library (or even no libraries at all).
<html>
<head>
<title>An example</title>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
<script>
function call_counter(url, pk) {
window.open(url);
$.get('YOUR_VIEW_HERE/'+pk+'/', function (data) {
alert("counter updated!");
});
}
</script>
</head>
<body>
<button onclick="call_counter('http://www.google.com', 12345);">
I update object 12345
</button>
<button onclick="call_counter('http://www.yahoo.com', 999);">
I update object 999
</button>
</body>
</html>
Alternative approach
Instead of placing the JavaScript code, you can change your link in this way:
<a target="_blank"
class="btn btn-info pull-right"
href="{% url YOUR_VIEW column_3_item.pk %}/?next={{column_3_item.link_for_item|urlencode:''}}">
Check It Out
</a>
and in your views.py:
def YOUR_VIEW_DEF(request, pk):
YOUR_OBJECT.objects.filter(pk=pk).update(views=F('views')+1)
return HttpResponseRedirect(request.GET.get('next')))
这篇关于如何调用django功能按钮点击的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
