如何从Django的请求获取多值密钥的所有值.GET QueryDict [英] how to obtain all values of a multi-valued key from Django's request.GET QueryDict

问题描述

Django文档在 http： //docs.djangoproject.com/en/dev/ref/request-response/#django.http.QueryDict.iteritems QueryDict.iteritems（）使用与 QueryDict .__ getitem __（）相同的最后一个逻辑值，这意味着如果该键具有多个值，则 __ getitem __（）返回最后一个值。

让我们说 print request.GET 看起来像这样：

< QueryDict：{u'sex'：[u'1']，u'status'：[u'1'，u'2' ，u'3'，u'4']}>

如果我想要得到一个像因为 > iteritems 上面提到的行为：

  mstring = [] 
 for gk，gv in request.GET.ite ritems（）：
 mstring.append（％s =％s％（gk，gv））
 print&join（mstring）
  

获得没有太多循环的结果的最有效的方法是什么？

我应该提到我不是诉诸 QueryDict.urlencode（）因为该请求中有一些键，我不希望在字符串中。我可以改变字符串，并把这些key = value，但只是想知道是否有更好的方法来解决这个问题。我明白这个信息应该被明确提到。

解决方案

这应该是有效的：

  mstring = [] 
 for request.GET.iterkeys（）：＃for key in request.GET也可以。 
＃在这里添加过滤逻辑。 
 valuelist = request.GET.getlist（key）
 mstring.extend（valuelist中val的['％s =％s'％（key，val）]）
 print'& '.join（mstring）
  

The Django docs say at http://docs.djangoproject.com/en/dev/ref/request-response/#django.http.QueryDict.iteritems thatQueryDict.iteritems() uses the same last-value logic as QueryDict.__getitem__(), which means that if the key has more than one value, __getitem__() returns the last value.

Let's say print request.GET looks like this:

<QueryDict: {u'sex': [u'1'], u'status': [u'1', u'2', u'3', u'4']}>

If I want to get a string like sex=1&status=1&status=2&status=3&status=4 (standard HTTP GET stuff) the following code won't give the desired results because of the iteritems behavior mentioned above:

mstring = []
for gk, gv in request.GET.iteritems():
    mstring.append("%s=%s" % (gk, gv))
print "&".join(mstring)

What is the most efficient way to obtain the result that I want without too much looping?

Regards.

[EDIT]

I should mention that I am not resorting to QueryDict.urlencode() because there are some keys in that request.GET that I don't want in the string. I could alter the string and take those key=value out, but just wondering if there is a better way to go about this. I realize this information should have been explicitly mentioned.

解决方案

This should work:

mstring = []
for key in request.GET.iterkeys():  # "for key in request.GET" works too.
    # Add filtering logic here.
    valuelist = request.GET.getlist(key)
    mstring.extend(['%s=%s' % (key, val) for val in valuelist])
print '&'.join(mstring)

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