Django - 连续发送输出 [英] Django - Send Output Continually

问题描述

我想从django视图开始处理一些文件，我希望能够在处理文件时将文件的名称发送到浏览器。有没有办法这样做（容易）？我可以使用线程和ajax调用来实现，但是我现在想要最简单的解决方案。

I want to start processing some files from a django view and I want to be able to send the name of the files to the browser as they are processed. Is there a way to do this (easily)? I could probably do this using threads and ajax calls, but I want the simplest solution for now.

推荐答案

我找到了我需要的在回答从安德烈·米勒提供的链接之一。

I found what I needed in an answer from one of the links that Andre Miller provided.

我发现可以通过一个迭代器到HttpResponse，所以我使用这个代码和它工作：

I found out that's possible to pass an iterator to HttpResponse so I used this code and it worked:

def import_iter():
    """ Used to return output as it is generated """
    # First return the template
    t = loader.get_template('main/qimport.htm')
    c = Context()
    yield t.render(c)
    # Now process the files
    if req.method == 'POST':
        location = req.POST['location']
        if location:
            for finfo in import_location(location):
                yield finfo+"<br/>"

return HttpResponse(import_iter())

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