在Django Admin中创建list_filter的自定义过滤器 [英] Creating Custom Filters for list_filter in Django Admin

问题描述

我想为django管理员定制过滤器，而不是正常的is_staff和is_superuser。我已经在Django文档中阅读过 list_filter 。
自定义过滤器以这种方式工作：

I would like to make custom filters for django admin instead of the normal 'is_staff' and 'is_superuser'. I have read this list_filter in Django docs. Custom Filters work in this way:

from datetime import date

from django.utils.translation import ugettext_lazy as _
from django.contrib.admin import SimpleListFilter

class DecadeBornListFilter(SimpleListFilter):
    # Human-readable title which will be displayed in the
    # right admin sidebar just above the filter options.
    title = _('decade born')

    # Parameter for the filter that will be used in the URL query.
    parameter_name = 'decade'

    def lookups(self, request, model_admin):
        """
        Returns a list of tuples. The first element in each
        tuple is the coded value for the option that will
        appear in the URL query. The second element is the
        human-readable name for the option that will appear
        in the right sidebar.
        """
        return (
            ('80s', _('in the eighties')),
            ('90s', _('in the nineties')),
        )

    def queryset(self, request, queryset):
        """
        Returns the filtered queryset based on the value
        provided in the query string and retrievable via
        `self.value()`.
        """
        # Compare the requested value (either '80s' or '90s')
        # to decide how to filter the queryset.
        if self.value() == '80s':
            return queryset.filter(birthday__gte=date(1980, 1, 1),
                                    birthday__lte=date(1989, 12, 31))
        if self.value() == '90s':
            return queryset.filter(birthday__gte=date(1990, 1, 1),
                                    birthday__lte=date(1999, 12, 31))

class PersonAdmin(ModelAdmin):
    list_filter = (DecadeBornListFilter,)

但是我已经为list_display定制了这样的功能：

But i have already made custom functions for list_display like this:

def Student_Country(self, obj):
    return '%s' % obj.country
Student_Country.short_description = 'Student-Country'

我可以使用list_filter中的list_display的自定义函数，而不是为list_filter编写新的自定义函数？任何建议或改进是受欢迎的..需要一些指导这个...谢谢...

Is it possible i could use the custom functions for list_display in list_filter instead of writing a new custom function for list_filter? Any suggestions or improvements are welcome.. Need some guidance on this... Thanks...

推荐答案

这是你想要的。检查以下链接
https://djangosnippets.org/snippets/2885/

Is this you want. Check the below link https://djangosnippets.org/snippets/2885/

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