实现UUID作为主键 [英] Implementing UUID as primary key

问题描述

我需要实现UUID作为主键，但我不知道如何在Django中执行。

I need to implement UUID as primary key but I'm not sure how to do it in Django.

我的代码

class LinkRenewAd(models.Model): # This model will generate the uuid for the ad renew link
    def make_uuid(self):
        return str(uuid.uuid1().int>>64)

    uuid = models.CharField(max_length=36, primary_key=True, default=make_uuid, editable=False)
    main = models.ForeignKey(Main)
    expiration_date = models.DateTimeField()
    date_inserted = models.DateTimeField(auto_now_add=True)
    date_last_update = models.DateTimeField(auto_now=True)   

当我尝试在南方生成这个新模型时，我收到了错误：

When I try to generate this new model on South I got the error:

TypeError: make_uuid() takes exactly 1 argument (0 given)

推荐答案

self 意味着你需要传递一个实例。在你的情况下，你没有一个实例，这就是为什么你看到一个错误的参数的奇怪的错误。

self means you need to pass in an instance. In your case, you don't have an instance, which is why you are seeing the strange error of a missing argument.

为了解决你的问题，移动方法生成模型类的字段：

To solve your problem, move the method that generates the field of out of your model class:

def make_uuid():
    return str(uuid.uuid1().int>>64)

class Foo(models.Model):
    id = models.CharField(max_length=36, primary_key=True, default=make_uuid)

但是，这不是理想的解决方案。最好创建一个自定义数据库字段。由于这是一个常见的问题，所以有很多版本。我个人喜欢 david cramer的版本。

However, this is not the ideal solution. It is better to create a custom database field. As this is a common problem, there are many versions out there. I personally like david cramer's version.

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