Django ModelChoiceField下拉框定制人口 [英] Django ModelChoiceField drop down box custom population

问题描述

我有一个下拉框，由一个模型选项中的过滤的对象列表填充。目前，下拉列表显示每个选项的名称。如何从同一个表中显示另一个属性？

I have a dropdown box that is being populated by a filtered list of objects from a model "Options". Currently, the dropdown list displays the names of each option. How would I get it to display another attribute from the same table?

self.fields['name'] = forms.ModelChoiceField(queryset = Options.objects.filter(option_type = s), label = field_label, required=False) 

快速示例：下拉框目前显示汽车的名称：Camero，Nissan，Honda
我该如何让它显示每辆车的颜色（黑色，黑色，白色）。请注意，颜色也是选项表中的一个字段。

Quick example: drop down box currently displays the names of the cars: "Camero, Nissan, Honda" How would I get it to display the color of each car ("black, black, white"). Note that the color is also a field in the Option table.

推荐答案

您可以覆盖 label_from_instance 在 ModelChoiceField 在构建后。

You can override the label_from_instance on the ModelChoiceField after it's constructed.

self.fields['name'] = forms.ModelChoiceField(queryset = Options.objects.filter(option_type = s), label = field_label, required=False)
self.fields['name'].label_from_instance = lambda obj: "{0} {1}".format(obj.name, obj.color)

根据注释更新仅显示一次颜色： / p>

Update based on comment to only show the color once:

class MyModelChoiceField(forms.ModelChoiceField):
     def __init__(self, *args, **kwargs):
          super(MyModelChoiceField, self).__init__(self, *args, **kwargs)
          self.shown_colors = []


     def label_from_instance(self, obj):
          if obj.color not in self.shown_colors:
               self.shown_colors.append(obj.color)
               return "{0} {1}".format(obj.name, obj.color)
          else:
               return obj.name


self.fields['name'] = MyModelChoiceField(queryset = Options.objects.filter(option_type = s), label = field_label, required=False)

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