如何解码url到python，django中的路径 [英] How to decode url to path in python, django

问题描述

我需要将url转换为路径，我得到的是这个url如下：

Hi I need to convert url to path, what i got is this url as bellow:

url = u'/static/media/uploads/gallery/Marrakech%2C%20Morocco_be3Ij2N.jpg'

如下所示：

path = u'/static/media/uploads/gallery/Marrakech, Morocco_be3Ij2N.jpg'

thx。

推荐答案

使用 urllib.unquote 解码％ -encoded string：

Use urllib.unquote to decode %-encoded string:

>>> import urllib
>>> url = u'/static/media/uploads/gallery/Marrakech%2C%20Morocco_be3Ij2N.jpg'
>>> urllib.unquote(url)
u'/static/media/uploads/gallery/Marrakech, Morocco_be3Ij2N.jpg'

使用 urllib.quote 或 urllib.quote_plus ，你可以回来：

Using urllib.quote or urllib.quote_plus, you can get back:

>>> urllib.quote(u'/static/media/uploads/gallery/Marrakech, Morocco_be3Ij2N.jpg')
'/static/media/uploads/gallery/Marrakech%2C%20Morocco_be3Ij2N.jpg'

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