在其他应用模型中导入应用模型类 [英] Import app model class in another app model

问题描述

我有2个应用程序：同事和服务，每个都有自己的models.py

我可以从services.models导入服务。

当我在服务models.py中尝试从coworkers.models import Status获取此错误消息：

追溯（最近的最后一次呼叫）：文件
/ Users / lucas / Documents / projetos / cwk-manager / lib / python2.7 / site-packages / Django-1.4.3-py2.7.egg / django / core / management / commands / runserver.py，
line 91，in inner_run
self.validate（display_num_errors = True）文件/Users/lucas/Documents/projetos/cwk-manager/lib/python2.7/site-packages/Django-1.4.3-py2.7.egg/django/core /management/base.py，
第266行，验证
num_errors = get_validation_errors（s，app）文件/Users/lucas/Documents/projetos/cwk-manager/lib/python2.7/ site-packages / Django-1.4.3-py2.7.egg / django / core / management / validation.py，
line 30，i get_validation_errors
for（app_name，error）in get_app_errors（）。items（）：File/Users/lucas/Documents/projetos/cwk-manager/lib/python2.7/site-packages/Django-1.4。 3-py2.7.egg / django / db / models / loading.py，第158行，get_app_errors
self._populate（）文件/ Users / lucas / Documents / projetos / cwk-manager / lib / python2.7 / site-packages / Django-1.4.3-py2.7.egg / django / db / models / loading.py，第64行，在_populate
self.load_app（app_name，True）文件 /Users/lucas/Documents/projetos/cwk-manager/lib/python2.7/site-packages/Django-1.4.3-py2.7.egg/django/db/models/loading.py，第88行， load_app
models = import_module（'。models'，app_name）文件/Users/lucas/Documents/projetos/cwk-manager/lib/python2.7/site-packages/Django-1.4.3-py2.7
第35行，import_module
导入（名称）文件/ Users / lucas / Documents / projetos / cwk-manager /cwk-manager/cwk_manager/coworkers/models.py，
第2行，在
从services.models导入服务文件/Users/lucas/Documents/projetos/cwk-manager/cwk-manager/cwk_manager/services/models.py，
第5行，
class Services（models.Model）：文件/Users/lucas/Documents/projetos/cwk-manager/cwk-manager/cwk_manager/services/models.py，
第11行，在Services
status = models.ForeignKey（Status）NameError：name'Status'未定义

-

coworker models.py

  from django.db import models 
 from services.models import Services 
 
 class状态（models.Model）：
 status_name = models.CharField（max_length = 50）
 status_description = models.TextField（blank = True，null = True）
 
 class Meta：
 
 verbose_name =状态
 verbose_name_plural =状态
 
 def __unicode__ （self）：
 return self.status_name 
  

服务models.py

 从django.db导入模型
从进程状态
 
＃此表包含有关计划和其他一般服务的所有信息。 
 class Services（models.Model）：
 service_name = models.CharField（max_length = 100）
 service_description = models.TextField（blank = True，null = True）
 service_price = models.DecimalField（max_digits = 7，decimal_places = 2，blank = True，null = True）
 creation_date = models.DateField（auto_now_add = True）
 last_update = models.DateField（auto_now = True）
 status = models.ForeignKey（Status）
 
 class Meta：
 
 verbose_name =Services
 verbose_name_plural =Services
 
 def __unicode __（self）：
 return self.service_name 
  

-
有人可以帮我看看我做错了什么？

提前感谢！

解决方案

在Django 1.6.5这里：

 进口同事
 status = models.ForeignKey（coworkers.models.Status）
  

应该是这样的：

  import joorkers 
 status = models.ForeignKey（coworkers.Status）$ b $我现在（现在）知道OP使用的是Django 1.4.3，而且一些答案可能会解决这个问题。在那个版本的Django。但是，花了一段时间才能注意到版本，而这些答案在1.6.5中不起作用。
 
 
 
干杯！
 
I got 2 app: coworkers and services, each one with its own models.py

In coworkers models.py, I can "from services.models import Services".

When I try to "from coworkers.models import Status" in services models.py, I get this error message:

  
Traceback (most recent call last):   File
  "/Users/lucas/Documents/projetos/cwk-manager/lib/python2.7/site-packages/Django-1.4.3-py2.7.egg/django/core/management/commands/runserver.py",
  line 91, in inner_run
      self.validate(display_num_errors=True)   File "/Users/lucas/Documents/projetos/cwk-manager/lib/python2.7/site-packages/Django-1.4.3-py2.7.egg/django/core/management/base.py",
  line 266, in validate
      num_errors = get_validation_errors(s, app)   File "/Users/lucas/Documents/projetos/cwk-manager/lib/python2.7/site-packages/Django-1.4.3-py2.7.egg/django/core/management/validation.py",
  line 30, in get_validation_errors
      for (app_name, error) in get_app_errors().items():   File "/Users/lucas/Documents/projetos/cwk-manager/lib/python2.7/site-packages/Django-1.4.3-py2.7.egg/django/db/models/loading.py", line 158, in get_app_errors
      self._populate()   File "/Users/lucas/Documents/projetos/cwk-manager/lib/python2.7/site-packages/Django-1.4.3-py2.7.egg/django/db/models/loading.py", line 64, in _populate
      self.load_app(app_name, True)   File "/Users/lucas/Documents/projetos/cwk-manager/lib/python2.7/site-packages/Django-1.4.3-py2.7.egg/django/db/models/loading.py", line 88, in load_app
      models = import_module('.models', app_name)   File "/Users/lucas/Documents/projetos/cwk-manager/lib/python2.7/site-packages/Django-1.4.3-py2.7.egg/django/utils/importlib.py",
  line 35, in import_module
      import(name)   File "/Users/lucas/Documents/projetos/cwk-manager/cwk-manager/cwk_manager/coworkers/models.py",
  line 2, in 
      from services.models import Services   File "/Users/lucas/Documents/projetos/cwk-manager/cwk-manager/cwk_manager/services/models.py",
  line 5, in 
      class Services(models.Model):   File "/Users/lucas/Documents/projetos/cwk-manager/cwk-manager/cwk_manager/services/models.py",
  line 11, in Services
      status = models.ForeignKey(Status) NameError: name 'Status' is not defined
--

coworker models.py
from django.db import models
from services.models import Services

class Status(models.Model):
    status_name = models.CharField(max_length=50)
    status_description = models.TextField(blank=True, null=True)

    class Meta:

        verbose_name = "Status"
        verbose_name_plural = "Status"

    def __unicode__(self):
        return self.status_name
services models.py
from django.db import models
from coworkers.models import Status

# This table contains all the information about plans and other general services provided.
class Services(models.Model):
    service_name = models.CharField(max_length=100)
    service_description = models.TextField(blank=True, null=True)
    service_price = models.DecimalField(max_digits=7, decimal_places=2, blank=True, null=True)
    creation_date = models.DateField(auto_now_add=True)
    last_update = models.DateField(auto_now=True)
    status = models.ForeignKey(Status)

    class Meta: 

        verbose_name = "Services"
        verbose_name_plural = "Services"

    def __unicode__(self):
        return self.service_name
--
Can someone help me to see what I am doing wrong?

Thanks in advance! 
解决方案
In Django 1.6.5 this:
import coworkers
status = models.ForeignKey(coworkers.models.Status)
Should be this:
import coworkers
status = models.ForeignKey(coworkers.Status)
I am (now) aware the the OP is using Django 1.4.3 and that some of the answers may solve this in that version of Django. However, it took me a while to notice the version and those answers do not work in 1.6.5.

Cheers!

                        
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