Django：如何让模型继承自？ [英] Django: How do I get the model a model inherits from?

问题描述

可能重复：

获取python类父类

我有一个： / p>

I have a:

class Animal(models.Model):
    pass

class Cat(Aminal):
    pass

class StreetCat(Cat):
    pass

How can I find out the model a model inherits from?

推荐答案

您可以在python中获取直接超类， code> __ base __

You can get the direct superclass in python through __base__

>>> StreetCat.__base__ is Cat
>>> True

__基础__ 将为您提供一个元组所有的父类，如果你有多个基类 class Foo（A，B）

__bases__ will get you a tuple of all parent classes if you have multiple base classes class Foo(A, B)

更新感谢OP：以下django方法不检索抽象基类，从技术上讲，这些内存使用方法用于存储将每个继承的模型绑定到其父项的外键。警告！

Django还间接为继承的模型提供了一些帮助，这些模型是遍历超类的纯python方法的快捷方式。

Django also indirectly provides some helpers for inherited models which are shortcuts for the pure python methods of traversing the superclasses.

>>> StreetCat._meta.get_parent_list() 
[Out] : Set([Class Animal, Class Cat])

InheritedClass.parents 是所有父母的有序字典，因此如果您想要的话，以下内容可以让父母最多：

InheritedClass.parents is an ordered dictionary of all parents, so the following would work to get the upper most parent if you wanted:

>>> StreetCat._meta.parents.keys()[-1]

您还可以使用非django相关方法，如

You could also use a non django related method, something like

>>> StreetCat.__mro__[-3] 
# once you know that BaseModel is an Object, and since all defined models subclass 
# the BaseModel, [-3] is the first class that subclasses models.Model

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