在Django模板中显示反向多对多 [英] Displaying reverse many-to-many in Django Templates
问题描述
我正在为小型销售CRM应用程序创建一个警报/通知系统。
我有一个Lead_Contact模型,用于存储客户端的名称,地址等,以及一个Contact_Notifier模型,用于跟踪客户端首次联系,最后一次联系,以及何时接下来要联系他们。
I'm in the midst of creating an alarm/notification system for a small Sales CRM app. I have a Lead_Contact model that is used to store a client's name, address, etc. as well as a Contact_Notifier models that is being used to keep track of when a client was first contacted, the last contact, and when we are going to next contact them.
为了参考,以下是模型的相关片段:
For reference, here is the relevant snippets of the models:
class Lead_Contact(models.Model):
first_contacted = models.ManyToManyField('Contact_Notifier', related_name='first_contact', null=True,blank=True)
last_contacted = models.ManyToManyField('Contact_Notifier', related_name='last_contact', null=True,blank=True)
next_contacted = models.ManyToManyField('Contact_Notifier', related_name='next_contact', null=True,blank=True)
和
class Contact_Notifier(models.Model):
WHEN_CHOICES = (
('F', 'First'),
('L', 'Last'),
('N', 'Next'),
)
when_contact = models.CharField(max_length=1, choices=WHEN_CHOICES)
contact_date = models.DateField(blank = True, null=True)
contact_time = models.TimeField(blank = True, null=True)
contact_message = models.TextField(blank=True)
is_finished = models.BooleanField(default=False)
我创建了一个视图函数,它基本上过滤了Contact_Notifier以显示CRM应用程序的各个用户的所有next_contact对象,如:
I have created a view function that essentially filters Contact_Notifier to display all of my next_contacted objects for the individual users of the CRM app, like such:
def urgent_notifier(request, template_name='urgent_results.html'):
error = ""
selected_user = user_filter(request)
results=Contact_Notifier.objects.filter( Q(user=selected_user) | Q(user="AU")).filter(when_contact = 'N').filter(contact_date__lte=datetime.date.today())
return render_to_response(template_name, {'issues': results, 'error': error})
现在在我的模板中,我显示了我的查询,但是当我出现问题尝试从Lead_Contact模型显示字段;我已经阅读了Django书和Django项目文档,但我似乎无法使反向关系显示工作!以下是相关的模板代码:
Now in my template, I'm displaying my queryset, but having issues when I attempt to display fields from the Lead_Contact model; I've read over the Django book and Django Project documentation, but I just can't seem to make the reverse relationship displays work! Here's the relevant template code:
{% if issues %}
{% for issue in issues %}
<form action="/results/{{issue.id}}/normalize/" method="post">
<input type="submit" value="remove" /><b>Contact Time:</b> {{issue.contact_date}} <b> at </b> {{issue.contact_time}} <b>via</b> {{issue.get_contact_type_display}} <br>
<!-- Here is where my problems start -->
{% for item in issue.lead_contact_set.all %}
{{ item.salutation }} <a href="../results/{{issue.pk}}/"> {{ item.first_name }} {{ item.last_name }} </a> <b> Phone:</b> {{ item.phone_1 }} {{ issue.phone_2 }} <b>email:</b> {{item.email}} <br>
{% endfor %}
</form>
{% endfor %}
{% endif %}
还尝试使用相关名称:
{% for item in issue.next_contact.all %}
我做错了什么?
推荐答案
您在 Lead_Contact
和 Contact_Notifier
之间有三个关系,您已正确定义了 related_name
属性。所以这些是你应该用来跟随你的反向关系的名字:
You have three relationships between Lead_Contact
and Contact_Notifier
, and you've correctly defined related_name
attributes for all of them. So those are the names you should be using to follow your reverse relationship:
{% for item in issue.first_contact.all %}
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