Django管理员通过ImageField链接到图像 [英] Django admin link to image via ImageField

问题描述

我已经设置了一个包含以下字段的活动的Django模型：

I've set up a Django model of an activity which contains following field:

class Activity(models.Model):
    ...
    thumbnail = models.ImageField(upload_to="thumbs/", blank=True, null=True)

通过管理界面，我可以将正确放置在主目录的thumbs文件夹中的图像上传。当我尝试编辑我创建的活动时，界面说：目前：thumbs / image.png 这是一个超链接，指向 http：/ /localhost:8000/media/thumbs/image.png 。当我点击这个链接，我得到404页面找不到错误。如何让链接正确地指向我上传的图像？如果可能，如何直接在管理界面中显示图像？

Via the admin interface I can upload an image that is put correctly in the thumbs folder of the home directory. When I try to edit the activity I created, the interface says: Currently: thumbs/image.png which is a hyperlink that points to http://localhost:8000/media/thumbs/image.png. When I click this link, I get a 404 page not found error. How can I get the link to point correctly to the image I uploaded? And if possible, how can I display the image directly in the admin interface?

编辑：

MEDIA_ROOT = '/用户/.../ mysite的/媒体/';
MEDIA_URL = 'http：// localhost：8000 / media /';

MEDIA_ROOT = '/Users/.../mysite/media/'; MEDIA_URL = 'http://localhost:8000/media/';

URL的内容.py：

Contents of urls.py:

from django.conf.urls import patterns, include, url
from django.contrib import admin
admin.autodiscover()

urlpatterns = patterns('',
    url(r'^admin/', include(admin.site.urls)),
)

谢谢！

推荐答案

settings.py

from django.conf.urls import patterns, include, url
from django.conf.urls.static import static
from django.contrib import admin
from django.contrib.staticfiles.urls import staticfiles_urlpatterns

admin.autodiscover()

urlpatterns = patterns('',
    url(r'^admin/', include(admin.site.urls)),
)+ static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT)

urlpatterns += staticfiles_urlpatterns()

models.py

class Activity(models.Model):
    ...
    thumbnail = models.ImageField(upload_to="thumbs/", blank=True, null=True)

    def image_(self):
        return '<a href="/media/{0}"><img src="/media/{0}"></a>'.format(self.thumbnail)
    image_.allow_tags = True



class AdminName(admin.ModelAdmin):
    .........
    list_display = ('image_',)

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