Django没有返回一个HttpResponse对象 [英] Django didn't return an HttpResponse object

问题描述

我做了一个简单的宠物店应用程序，只是添加了搜索框功能，我收到这个错误

I made a simple pet store app and just added search box feature and I received this error

ValueError at /pet/search/
The view mysite.pet.views.search_page didn't return an HttpResponse object.

我试图将render_to_response更改为HttpResponseRedirect，但仍然有相同的错误。

I tried to change render_to_response into HttpResponseRedirect but still got the same error.

链接回视图中的search_page函数。

Linking back to my search_page function in views.

def search_page(request):
    form = SearchForm()
    if request.method == "POST":
        f = SearchForm(request.POST)
        if f.is_valid():
            Pets = Pet.objects.filter(animal = f.cleaned_data["text"])
            return HttpResponseRedirect("search.html",{"Pets":Pets},{"form":form})
        else:
            return render_to_response("search.html",{"form":form} , context_instance = RequestContext(request))

我做了一些研究，我理解一个视图必须返回一个HttpResponse，当一个HttpRequest被创建和render_to_response只是一个快捷方式。有人帮助解释为什么这个功能将无法工作。谢谢你/ / p >

I did some research and I understand a view has to return a HttpResponse when a HttpRequest is made and render_to_response is just a shortcut.Can someone help explain why this function won't work.Thank you

推荐答案

你正在得到的问题，因为如果请求类型不是 POST

You are getting this problem because you havn't written a HttpResponse object if request type is not POST

为了克服这个在你的看法写somthing，将处理，如果请求类型不发布

To overcome this in your view write somthing which will process if request type is not post

def search_page(request):
    form = SearchForm()
    if request.method == "POST":
        f = SearchForm(request.POST)
        if f.is_valid():
            Pets = Pet.objects.filter(animal = f.cleaned_data["text"])
            return HttpResponseRedirect("search.html",{"Pets":Pets},{"form":form})



    return render_to_response("search.html",{"form":form} , context_instance = RequestContext(request))

希望这将有助于您感谢

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