在Django中如何使用这样的URL？ [英] How to have a URL like this in Django?

问题描述

如何在Django中使用 example.com/category/catename-operation / 之类的URL？

How can I have URLs like example.com/category/catename-operation/ in Django?

另外在某些情况下，用户输入一个空格分隔的类别，该怎么处理呢？
例如，如果用户将类别输入为我的家，则此类别的URL将成为
example.com/my home / which

Also in some cases the user enters a space separated category, how can I handle that? E.g if the user enters the category as "my home", then the URL for this category will become example.com/my home/ which is not a valid URL.

如何处理这些事情？

推荐答案

如果您想保持网址漂亮，例如，当用户输入我的类别时，您可以在URL中使用我的类别而不是我的％20category。我建议您查看SlugField（ http://docs.djangoproject.com / en / dev / ref / models / fields /＃slugfield ），并使用ModelAdmin的prepopulated_fields属性预先填充该slugfield。

If you want to keep your URLs pretty, for example when a user enters "my category" you could have "my-category" instead of "my%20category" in the URL. I suggest you look into SlugField (http://docs.djangoproject.com/en/dev/ref/models/fields/#slugfield) and prepopulating that slugfield using ModelAdmin's prepopulated_fields attribute.

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