打印一个以上家庭的人员列表，每个家庭有多个电话号码 [英] printing a list of persons with more than one home, each home with more than one phone number

问题描述

我有一个班级人员可以有几个家庭，每个家庭都有一个或多个电话号码。

我已经定义了类，但现在我试图创建一个视图，列出每个人，其所有的家庭和所有的电话号码为每个家庭住址...类似于：

 约翰·史密斯
 123假货str 
 305-99-8877 
 305-99-8876 
 321橡木路
 444-98-7654 
 
 peter guy 
 453 north ave ... 
  

到目前为止，我有这样的东西：

（在我的views.py上）

  def ViewAll请求）：
 people = Person.objects.all（）
 render_to_response（'viewall.html'，{'people'：people}）
  

（和我的模板）

  {％人民币％} 
 {{guy.name}} 
 {％if person.home_address_set.all％} 
 {{home_address}} 
 
 {％for ?? ????在???? ％} 
 #print每个房屋中的电话号码
 {％endfor％} 
 
 {％endif％} 
 {％endfor％} 
  

任何想法如何写我失踪？当然，如果有另一种方式（更好的更优雅或更有效的方式）做我需要的，我很乐意听到。

解决方案

你有什么似乎是三个嵌套的集合：人，家庭，电话号码。

步骤1 - 你如何在视图函数中写这个？

  for p in Person.objects.all（）：
 printperson，p 
 for h在p.home_address_set.all（）中：
打印home，h 
在h.phone_set.all（）中的ph：
打印phone，ph 
  

不要忽略这一步。如果您无法使其在视图功能中工作，您的模型是错误的。花费时间来获得此部分。

步骤2 - 将其转换为模板语法。

  {％for p on people％} 
 {％for h in p.home_address_set.all％} 
 {％fpr ph in h.phone_set.all％} 
 {％endfor％} 
 {％endfor％} 
 {％endfor％} 
  

结果应与您的查看功能相同。

I have a class Person which can have several Homes, each one with one or many Phone numbers.

I have defined the classes, but now i am trying to create a view wich list every person, with all its homes and all the phone numbers for each home address... something like:

john smith
123 fake str
  305-99-8877
  305-99-8876
321 oak road
  444-98-7654

peter guy
453 north ave...

so far i have something like this:

(on my views.py)

def ViewAll(request):
  people = Person.objects.all()
  render_to_response('viewall.html', {'people': people})

(and on my template)

{% for guy in people %} 
  {{ guy.name }}
  {% if person.home_address_set.all %}
    {{ home_address }}

    {% for ?????? in ???? %}
      #print phone numbers in each home
    {% endfor %}

  {% endif %}
{% endfor %}

any idea of how to write the for I'm missing? of course, if there is another way (a better more elegant or efficient way) of doing what I need, I would love to hear it.

解决方案

You have what appears to be three nested collections: Person, Home, Phone Number.

Step 1 - How would you write this in a view function?

for p in Person.objects.all():
    print "person", p
    for h in p.home_address_set.all():
         print " home", h
         for ph in h.phone_set.all():
             print "  phone", ph

Don't omit this step. If you can't make it work in a view function, your model is wrong. Take the time to get this part right.

Step 2 - Convert this into template syntax.

{% for p on people %}
    {% for h in p.home_address_set.all %}
        {% fpr ph in h.phone_set.all %}
        {% endfor %}
    {% endfor %}
{% endfor %} 

The results should be the same as your view function.

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