无法分配“< SimpleLazyObject：< User：XXX>&quot ;:”Comment.user“必须是“MyProfile”例 [英] Cannot assign "<SimpleLazyObject: <User: XXX>>": "Comment.user" must be a "MyProfile" instance

问题描述

你好我知道我在这里有两个问题。一个是simpleLazyObject问题，我可以用一种黑客的方式来解决它。另一个是Comment.user必须是一个MyProfile实例，我不知道如何修复。我觉得在某个地方，事情变得混乱了。

  def post（request，slug）：
 user = get_object_or_404（User，username__iexact = request.user）
 try：
 profile = MyProfile.objects.get（user_id = request.user.id）
＃如果是OneToOne字段，你可以：
＃profile = request.user.myprofile 
除了MyProfile.DoesNotExist：
 profile = None 
 post = get_object_or_404（Post，slug = slug）
 post.views + = 1＃增加视图数
 post.save（）＃并保存
 comments = post.comment_set.all（）
 comment_form = CommentForm（request.POST或None）
如果comment_form.is_valid（）：
 post_instance = comment_form.save（commit = False）
 post_instance.user = request.user #this是发生错误的地方，如果我把request.user。 id simpleLazyObject dissapears。 
 post_instance.path = request.get_full_path（）
 post_instance.post = post 
 post_instance.save（）
 
 context_dict = {
'post'：帖子，
'profile'：个人资料，
'comments'：评论，
'comment_form'：comment_form 
} 
 
返回呈现（请求， main / post.html'，context_dict）
  

我不知道comment.user是什么意思必须是myprofile实例。

在我的评论应用中，models.py我有

  class评论（models.Model）：
 user = models.ForeignKey（MyProfile）
  

我的帐户应用程序，models.py我有

  class MyProfile（UserenaBaseProfile）：
 user = models.OneToOneField ，unique = True，verbose_name = _（'user'），related_name ='my_profile'）
  

不确定如何解决这个问题，任何帮助将被高度赞赏...

解决方案

评论有ForeignKey到MyProfile，但是在触发错误的行中，您提供了一个用户模型。
正确的方式是：

  my_p = MyProfile.objects.get（user = request.user）
 post_instance.user = my_p 
  

请注意，您使用：

  MyProfile.objects.get（user = request.user）
  

而不是id字段。虽然幕后django使用id字段作为数据库中的真正的外键，但在代码中您可以使用该对象。关系字段是django执行关系查询的魔术的描述符。

Hello I know I have two problems here. one is simpleLazyObject issue which I can fix it with kinda hackish way. The other is "Comment.user" must be a "MyProfile" instance which I don't know how to fix. I think somewhere in the way, things got mixed up.

def post(request, slug):
        user = get_object_or_404(User,username__iexact=request.user)
        try:
            profile = MyProfile.objects.get(user_id=request.user.id)
            # if it's a OneToOne field, you can do:
            # profile = request.user.myprofile
        except MyProfile.DoesNotExist:
            profile = None
        post = get_object_or_404(Post, slug=slug)
        post.views += 1  # increment the number of views
        post.save()      # and save it
        comments = post.comment_set.all()
        comment_form = CommentForm(request.POST or None)
        if comment_form.is_valid():
            post_instance = comment_form.save(commit=False)
            post_instance.user = request.user #this is where error is occuring, if I put request.user.id simpleLazyObject dissapears.
            post_instance.path = request.get_full_path()
            post_instance.post = post
            post_instance.save()

        context_dict = {
            'post' :post,
            'profile' :profile,
            'comments':comments,
            'comment_form': comment_form
        }

        return render(request, 'main/post.html', context_dict)

I'm not sure what it means by comment.user must be myprofile instance.

in my comments app, models.py I have

class Comment(models.Model):
    user = models.ForeignKey(MyProfile)

and in my accounts app, models.py I have

class MyProfile(UserenaBaseProfile):
    user = models.OneToOneField(User, unique=True, verbose_name=_('user'), related_name='my_profile')

I'm not sure how to fix this problem, any help will be highly appreciated...

解决方案

Comment has ForeignKey to MyProfile, yet in the line that triggers the error you provide a User model. The correct way would be:

my_p = MyProfile.objects.get(user=request.user)
post_instance.user = my_p

Note that you use:

MyProfile.objects.get(user=request.user)

And not the id field. Although behind the scenes django does use the id field as the real foreign key in the database, in your code you use the object. A relational field is a descriptor where django does the magic to run a relational query.

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