创建成员ID的下拉菜单 [英] Creating a drop-down menu of Member IDs

问题描述

我有一个模型会员，包含一个名为member_id的规范。

  class Member（models.Model）：
 member_id = models.SlugField（max_length = 10）
 name = models.CharField（max_length = 200）
 gender = models.CharField（max_length = 1，choices = GENDER_CHOICES）
 mobile = models .SlugField（max_length = 20）
 def __str __（self）：
 return self.name 
  

我想创建一个存储成员编号的下拉菜单，供用户从 select_member.html 中选择。

现在，我在 forms.py 中有这个：（很确定它是错误的）

$ b $
memberid = forms.ModelChoiceField（queryset = Member.member_id.objects.all（））

以下视图：

  class selectView（generic.ListView）：
 template_name ='expcore / select_member.html'
 model = Activity 
 
 def select_member（request）：
 form = SelectForm ）
如果request.method =='POST'：
 form = SelectForm（request.POST）
如果form.is_valid（）：
返回HttpResponseRedirect（'/ questions /' ）
 else：
 form = SelectForm（）
 return render（request，'select_member.html'，{'form'：form}）
  

url：

  url（r'^活动/（？P< activityname> [^ /] +）/ member / $'，views.SelectView.as_view（），name ='select_member'），
  

我的select_member.html中没有任何内容，因为我不知道该怎么做。

有人可以通过表单，查看和HTML来帮助我吗？我想能够调用所有的成员ID，但是Member.member_id.objects.all（）不起作用。

另外，如果有人能告诉我如何正确调用所有存储的成员ID，而不是不正确的Member.member_id.objects.all（），那将是很棒的。

解决方案

Member.objects.values（'member_id'）给出了具有值结构的字典列表作为{'member_id'：value}。

如果你只想要ids，你可以使 Member.objects.values_list（'member_id'，flat = True ）

无论如何，您尝试使用ModelChoiceField，它期望使用Model实例的查询，并尝试传递给它


ModelChoiceField（queryset = Member.objects.all（），to_field_name ='member_id' ）
通常， ModelChoiceFields 将id作为选项，但可以用 to_field_name 覆盖它：

https://github.com/django/django/blob/master/django/forms/models.py# L1129-L1144

I have a model Member that includes a specification called member_id.

class Member(models.Model):
    member_id = models.SlugField(max_length=10)
    name = models.CharField(max_length=200)
    gender = models.CharField(max_length=1, choices=GENDER_CHOICES)
    mobile = models.SlugField(max_length=20)
    def __str__(self):
         return self.name 

I want to create a drop-down menu of stored member ID's for the user to choose from in select_member.html.

Right now, I have this in forms.py: (pretty sure it's wrong)

class SelectForm(forms.Form):
    memberid = forms.ModelChoiceField(queryset=Member.member_id.objects.all())

The following view:

class SelectView(generic.ListView):
  template_name = 'expcore/select_member.html'
  model = Activity

  def select_member(request):
    form = SelectForm()
    if request.method == 'POST':
      form = SelectForm(request.POST)
      if form.is_valid():
        return HttpResponseRedirect('/questions/')
    else:
      form = SelectForm()
    return render(request, 'select_member.html', {'form': form})

The url:

url(r'^activity/(?P<activityname>[^/]+)/member/$', views.SelectView.as_view(), name='select_member'),

And nothing in my select_member.html because I'm not sure what to put.

Can someone help me out with the form, view, and HTML? I want to be able to call all the member IDs but Member.member_id.objects.all() doesn't work.

Also, it would be great if someone could tell me how to correctly call all the stored member IDs - instead of the incorrect Member.member_id.objects.all().

解决方案

Member.objects.values('member_id') gives you list of dictionaries with values structured as {'member_id': value}.

If you just want the ids, you can make Member.objects.values_list('member_id', flat=True) which will just give you list of member ids.

Anyways you try to use ModelChoiceField which expects a queryset of Model instances and you try to pass to it a list of slugs.

What you want to do is ModelChoiceField(queryset=Member.objects.all(), to_field_name='member_id') Normally ModelChoiceFields gets id as option, but you can override it with to_field_name :

https://github.com/django/django/blob/master/django/forms/models.py#L1129-L1144

这篇关于创建成员ID的下拉菜单的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！