尝试创建一个对象的元组创建一个对象和一个查询 [英] Trying to create a tuple of objects create an object and a queryset

问题描述

我需要遍历模板中的一个元组，但是从我建立的代码中我得到一个对象（专辑）和一个查询（照片）的元组。问题是我们现在在模板中如何迭代？

I need to iterate through a tuple in the template, but from the code i've built i am getting a tuple of an object (album) and a queryset (photo). The problem is how do i iterate over them now in the template?

模型：

class Album(models.Model):
    title = models.CharField('כותרת', max_length=100, db_index=True)
    created = models.DateTimeField('תאריך פרסום', auto_now_add=True)
    creator = models.ForeignKey(User, related_name='galleries_creator', verbose_name='נכתב ע"י')

class Photo(models.Model):
    title = models.CharField('כותרת', max_length=100)
    album = models.ForeignKey(Album, verbose_name='שייך לאלבום')
    photo = models.ImageField('תמונה', blank=True, upload_to=get_image_path)
    photo_mid = models.ImageField('תמונה בינונית', blank=True, upload_to='images/galleries/mid/', editable=False)
    photo_thumb = models.ImageField('תמונה קטנה', blank=True, upload_to='images/galleries/thumbs/', editable=False)
    created = models.DateTimeField('תאריך פרסום', auto_now_add=True)
    is_landscape = models.NullBooleanField(blank=True, verbose_name='האם תמונת לנדסקייפ', editable=False)

查看：

def index(request):
    albums = Album.objects.all().order_by('?')[:10]
    album_list = []
    for album in albums:
        album_list.append((album, Photo.objects.filter(album=album).order_by('?')[:1]))
    return render_to_response('galleries/index.html',{'albums':album_list},  context_instance=RequestContext(request))

模板：

{% for album, photo in albums %}
    <div class="polaroid" id="picture_{{ forloop.counter }}">
        <img src="{{ MEDIA_URL }}{{ photo.photo }}" alt="Picture #{{ forloop.counter }}" />
        <p class="caption"><p class="title">אלבום {{ forloop.counter }}</p><p>{{ album.creator.first_name }} {{ album.creator.last_name }}</p>
    </div>
{% endfor %}

正如我所见，我无法做照片。照片因为照片是一个列表，而不是一个对象，我真的不想为元组中的每张照片做一个for循环（只有一张照片，所以这只是一个浪费）。

As i see it, i can't do photo.photo because photo is a list, not an object and i really don't want to do a for loop for every photo in the tuple (there is only one photo, so this is just a waste).

assert False album_list返回：

assert False album_list returns:

[(<Album: אלבום שני - ממשק מנהל>, [<Photo: אלבום 2 תמונה 2>]), (<Album: אלבום ראשון - ממשק מנהל>, [<Photo: אלבום 1 תמונה 7>]), (<Album: אלבום  נתן>, [<Photo: נסיון 4>])]

我可以在我的视图或模板中做什么来解决这个问题？

What can i do in my view or template to solve this?

推荐答案

如果每张专辑只有一张照片，那么为什么要切割queryset？只需使用索引获得第一个：

If there's only one photo per album you are after, then why slice the queryset? Just get the first one using index:

album_list.append((album, Photo.objects.filter(album=album).order_by('?')[0]))

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