如何解决django：UnboundLocalError [英] how to solve django: UnboundLocalError

问题描述

我有给定的视图和模板代码，当我尝试运行这个代码，我得到以下错误。当我搜索这种类型的错误，我发现，当变量和函数被赋予相同的名称时，但是在我的代码中无法更正。

 环境：
 
请求方法：GET 
请求URL：http://127.0.0.1:8000/budget/show/ 
 Django版本：1.2.5 
 Python版本：2.7.1 
安装的应用程序：
 ['django.contrib.admin'，
'django.contrib.auth'，
'django.contrib.contenttypes'，
'django.contrib.sessions'，
' django.contrib.sites'，
'django.contrib.messages'，
'mysite.bug'] 
安装的中间件：
（'django.middleware.common.CommonMiddleware' ，
'django.contrib.sessions.middleware.SessionMiddleware'，
'django.middleware.csrf.CsrfViewMiddleware'，
'django.contrib.auth.middleware.AuthenticationMiddleware'，
 'django.contrib.messages.middleware.MessageMiddleware'）
 
 
追溯：
文件/usr/lib/pymodules/python2.7/django/core/handlers/base .pyin get_response 100. response = callback（request，* callback_args，** callback_kwargs）
文件/home/nimesh/budman/mysite/../mysite/bug/views.py如图252所示。 
 return render_to_response（'budgetfinalform3.html'，{'account_number'：c，'period'：d，'month'：e，'year'：f，'formsetlist'：formset，'child'：child} ，context_instance = RequestContext（request））
 
异常类型：/ budget / show / 
中的UnboundLocalError异常值：赋值前引用的局部变量formset
  

plz帮助我删除此错误。

  def show（request）：
b = request.session [s1] 
c = request.session [s2] 
d = request.session [s3] 
a = account_period.objects.filter（ye ar = d）.values（'id'）
e = account_period.objects.filter（year = d）.values（'month'）
f = account_period.objects.filter（id = a）.values （'year'）
 
 try：
 child = account_tab.objects.filter（parent_account_number = c）.values（'account_number'）
 noofchild = account_tab.objects.filter parent_account_number = c）.count（）
除了account_tab.DoesNotExist：
 noofchild = 0 
如果noofchild！= 0：
 formsetlist = [] 
 
 
 for i in range（0，noofchild）：
 formsetlist.append（formset_factory（bu，extra = b））
如果request.method =='POST'：
 
 formsetlist2.append（formsetlist [i]（request.POST））
 
如果formsetlist2 [i] .is_valid（）：
j = 0 
 for formsetlist2 [ i] .forms：
z = account_tab.objects.get（account_number = child [i：（i + 1）]）
x = form.cleaned_data ['value'] 
y = account_period.objects .get（id = a [j：（j + 1）]）
 try：
 uip = budget.objects.get（account_no = child [i：（i + 1）]，account_period = a [j：（j + 1）]）
如果uip。 budget_amount！= x：
 
 uip.budget_amount = x 
 uip.save（）
 
除了budget.DoesNotExist：
 
w = budget （account_no = z，account_period = y，budget_amount = x，created_by_login ='me'）
 w.save（）
j = j + 1 
 pass 
 return HttpResponse '）
 
 
 else：
返回render_to_response（'budgetfinalform3.html'，{'account_number'：c，'period'：d，'month'：e，'year '：f，'formsetlist'：formset，'child'：child}，context_instance = RequestContext（request））
 #return HttpResponse（mes）
  

模板代码是

 < html> 
< head> 
< title> BUDGET< / title> 
< / head> 
< body> 
< h1  BUDGET MANAGEMENTS< / h1> 
< h2>您的帐号为：{{account_number}}。< / h2> < h2>您选择{{period}} {{month}}作为句点< / h2> 
 
 {％if form.errors％} 
< p style =color：red;> 
请更正以下错误{{form.errors | pluralize}}。 
< / p> 
 {％endif％} 
 
 
< form action =。方法=post> {％csrf_token％} 
 {form for formsetlist％中的formset} 
 {{formset.management_form}} 
 {{child}} 
 
< table> 
 {form for formset.forms％} 
 
 {％ifloop.counter == 0％} 
 {{child.1}} 
 {％ endif％} 
 {{form}} 
 {％endfor％} 
< / table> 
 {％endfor％} 
< input type =submitvalue =Submit> 
< / form> 
< / body> 
< / html> 
  

解决方案

  return render_to_response （'budgetfinalform3.html'，{'account_number'：c，'period'：d，'month'：e，'year'：f，'formsetlist'：formset，'child'：child}，context_instance = RequestContext ）
  

使用 formset 但它看起来/听起来像你的意思 formsetlist ：

  return render_to_response（'budgetfinalform3.html '，{'account_number'：c，'period'：d，'month'：e，'year'：f，'formsetlist'：formsetlist，'child'：child}，context_instance = RequestContext（request））
  

I have the given view and template code, when i try to run this code i get the following errors.when i searched about this type of error,i found that it happens when a variable and function is given the same name,but could't correct it in my code.

 Environment:

 Request Method: GET
 Request URL: http://127.0.0.1:8000/budget/show/
 Django Version: 1.2.5
 Python Version: 2.7.1
 Installed Applications:
 ['django.contrib.admin',
  'django.contrib.auth',
  'django.contrib.contenttypes',
  'django.contrib.sessions',
  'django.contrib.sites',
  'django.contrib.messages',
  'mysite.bug']
  Installed Middleware:
  ('django.middleware.common.CommonMiddleware',
  'django.contrib.sessions.middleware.SessionMiddleware',
  'django.middleware.csrf.CsrfViewMiddleware',
  'django.contrib.auth.middleware.AuthenticationMiddleware',
   'django.contrib.messages.middleware.MessageMiddleware')


 Traceback:
    File "/usr/lib/pymodules/python2.7/django/core/handlers/base.py" in get_response 100.                     response = callback(request, *callback_args,   **callback_kwargs)
    File "/home/nimesh/budman/mysite/../mysite/bug/views.py" in shown 252.             
    return render_to_response('budgetfinalform3.html', {'account_number': c,'period':d,'month':e,'year':f,'formsetlist': formset,'child':child},context_instance=RequestContext(request))

     Exception Type: UnboundLocalError at /budget/show/
     Exception Value: local variable 'formset' referenced before assignment                 

plz help me to remove this error.

def show (request):
b = request.session["s1"]
c = request.session["s2"]
d = request.session["s3"]
a = account_period.objects.filter(year=d).values('id')
e = account_period.objects.filter(year=d).values('month')
f = account_period.objects.filter(id = a).values('year')

try:
        child = account_tab.objects.filter(parent_account_number=c).values('account_number')
        noofchild = account_tab.objects.filter(parent_account_number=c).count()
except account_tab.DoesNotExist:
        noofchild = 0
if noofchild != 0 :   
       formsetlist = []


       for i in range(0, noofchild):
        formsetlist.append(formset_factory(bu, extra=b))
    if request.method == 'POST':

     formsetlist2.append(formsetlist[i](request.POST))

     if formsetlist2[i].is_valid():
       j=0
       for form in formsetlist2[i].forms:
         z = account_tab.objects.get(account_number = child[i:(i+1)])
         x = form.cleaned_data['value']
         y = account_period.objects.get(id=a[j:(j+1)])
         try:
                uip = budget.objects.get(account_no = child[i:(i+1)],account_period = a[j:(j+1)])
                if uip.budget_amount != x:

                  uip.budget_amount = x
                  uip.save()

         except budget.DoesNotExist:

                w = budget(account_no = z, account_period = y, budget_amount = x, created_by_login = 'me')
                w.save()
         j=j+1
       pass
       return HttpResponse('thanks')


    else:
             return render_to_response('budgetfinalform3.html', {'account_number': c,'period':d,'month':e,'year':f,'formsetlist': formset,'child':child},context_instance=RequestContext(request))
     #return HttpResponse(mes)

Template code is

    <html>
    <head>
    <title>BUDGET</title>
    </head>
    <body>
    <h1>BUDGET MANAGEMENTS</h1>
    <h2>Your Account Number is : {{ account_number }}.</h2> <h2>You Chose {{ period }} {{month}} as period</h2>   

    {% if form.errors %}
    <p style="color: red;">
        Please correct the error{{ form.errors|pluralize }} below.
    </p>
    {% endif %}


    <form action="." method="post">{% csrf_token %}
    {% for formset in formsetlist %}
    {{ formset.management_form }}
    {{child}}

    <table>
    {% for form in formset.forms %}

    {% if forloop.counter == 0  %}
     {{child.1}}
    {% endif%}
    {{ form }}
    {% endfor %}
    </table>   
    {% endfor %}
    <input type="submit" value="Submit">
    </form>
    </body>
    </html>

解决方案

return render_to_response('budgetfinalform3.html', {'account_number': c,'period':d,'month':e,'year':f,'formsetlist': formset,'child':child},context_instance=RequestContext(request))

Uses formset but it looks/sounds like you meant formsetlist:

return render_to_response('budgetfinalform3.html', {'account_number': c,'period':d,'month':e,'year':f,'formsetlist': formsetlist,'child':child},context_instance=RequestContext(request))

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