Django admin:按URL传递变量 [英] Django admin: pass variable by URL
问题描述
我想通过URL将变量传递给django管理员中的另一个页面。
它似乎不工作,我想传递变量/?name = hello,并通过request.GET.get [name,]来捕获它,但url变成/? e = 1。
如果我使用默认参数'q',它是有效的,但它会有冲突。
似乎这个问题只是django-admin。我需要通过url不要发布...
有谁知道如何解决这个问题
i want to pass a variable by URL to another page in django admin. it seems it is not working, i want to pass the variable "/?name=hello", and catch it by request.GET.get["name",""].but the url becomes "/?e=1" after it passed. if i use the default parameter'q', it works, but it will have a conflict. it seems this problem is django-admin only. and i need pass it by url not post... does any one knows how to solve this problem
谢谢
推荐答案
问题在于 name
不存在,当 get_query_set
尝试将其解析为模型字段。因此,一个
incorrectLookupParameters()
异常被引发,这反过来又重定向到不是很有帮助的e = 1url。 Django 1.4中引入了custom filterspecs,解决了这个问题。在此之前,一个可能的解决方案是动态地覆盖您的 ModelAdmins
get_changelist返回的
方法 ChangeList
)
The problem is that the lookup name
does not exist when the get_query_set
tries to resolve it as a model field. Thus an IncorrectLookupParameters()
exception is raised which in turn redirects to the not very helpful "e=1" url. This problem is solved in Django 1.4 with the introduction of custom filterspecs. Until then one possible solution is to dynamically overwrite the ChangeList
class returned by your ModelAdmins
get_changelist()
method.
此解决方案适用于Django 1.3:
This solution works on Django 1.3:
class MyModelAdmin(ModelAdmin):
def get_changelist(self, request, **kwargs):
changelist_class = super(MyModelAdmin, self).get_changelist(request,
**kwargs)
class CustomChangeList(changelist_class):
def __init__(self, request, *args, **kwargs):
self._name = request.GET.get('name')
super(CustomChangeList, self).__init__(request, *args, **kwargs)
def get_query_set(self, *args, **kwargs):
if self._name:
del self.params['name']
qs = super(CustomChangeList, self).get_query_set(*args, **kwargs)
if self._name:
return qs.filter([FILTER WHAT YOU WANT HERE...])
return qs
return CustomChangeList
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