Django表单__init __（）获取了关键字参数的多个值 [英] Django form __init__() got multiple values for keyword argument

问题描述

您好，我正在尝试使用修改的 __ init __ 表单方法，但是我遇到以下错误：

Hello, I'm trying to use a modified __init__ form method, but I am encountering the following error:

TypeError
__init__() got multiple values for keyword argument 'vUserProfile'

我需要通过 UserProfile 到我的表单，以获得 dbname 字段，我认为这是一个解决方案（我的表单代码）：

I need to pass UserProfile to my form, to get to dbname field, and I think this is a solution (my form code):

class ClienteForm(ModelForm):
class Meta:
    model = Cliente

def __init__(self, vUserProfile, *args, **kwargs):
    super(ClienteForm, self).__init__(*args, **kwargs)
    self.fields["idcidade"].queryset = Cidade.objects.using(vUserProfile.dbname).all()

调用构造函数 ClienteForm（）是成功的，并向我显示正确的形式。但是，当提交表单并使用POST调用构造函数时，我会得到以前描述的错误。

Calls to constructor ClienteForm() without POST are successful and show me the correct form. But when the form is submitted and the constructor is called with POST, I get the previously described error.

推荐答案

表单的 __ init __ 方法的签名，以便 vUserProfile 是第一个参数。但是在这里：

You've changed the signature of the form's __init__ method so that vUserProfile is the first argument. But here:

formPessoa = ClienteForm(request.POST, instance=cliente, vUserProfile=profile)

你通过 request.POST 作为第一个参数 - 除了这将是解释为 vUserProfile 。然后你也尝试通过 vUserProfile 作为关键字arg。

you pass request.POST as the first argument - except that this will be interpreted as vUserProfile. And then you also try to pass vUserProfile as a keyword arg.

真的，你应该避免更改方法签名，并从 kwargs 中获取新数据：

Really, you should avoid changing the method signature, and just get the new data from kwargs:

def __init__(self, *args, **kwargs):
    vUserProfile = kwargs.pop('vUserProfile', None)

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