如何更新用户对象而不创建新的？ [英] How to update User object without creating new one?

问题描述

以下内容适用于shell：

 >>>来自django.contrib.auth.models import User 
>>> user = User.objects.get（pk = 1）
>>> user.first_name = u'Some'
>>> user.last_name = u'Name'
>>> user.save（）
>>> user.first_name 
 u'Some'
>>> user.last_name 
 u'Name'
  

然后我尝试对表单做同样的事情：

 ＃forms.py 
 class UserForm（forms.ModelForm）：
 class Meta：
 model = User 
 fields = ['first_name'，'last_name'] 
 
 
＃views.py 
 def edit_names（request，template_name =registration / edit_names 。
如果request.method ==POST：
 form = UserForm（data = request.POST）
如果form.is_valid（）：
 user = form.save（commit = False）
 user.save（）
 url = urlresolvers.reverse（'my_account'）
返回HttpResponseRedirect（url）
 else：
 form = UserForm（instance = request.user）
 page_title = _（'编辑用户名'）
返回render_to_response（template_name，locals（），
 context_instance = RequestContext（request））
 
＃edit_names.html 
< form action =。 method =post> {％csrf_token％} 
< table> 
 {{form.as_table}} 
< tr>< td colspan =2> 
< input type =submit/> 
< / td>< / tr> 
< / table> 
< / form> 
  

我在浏览器中打开页面，看到两个字段名字和姓氏。当我填写字段并提交表单时，我会收到错误：

 异常类型：IntegrityError 
异常值：列用户名不唯一
  

我还尝试添加 ['username'] 到用户窗体中的字段列表。如果我使用我的用户名（作为request.user）提交表单，则表单显示errormessage：

 具有此用户名的用户已存在。 
  

如果我将用户名更改为某个唯一的名称，则会创建具有该用户名的新用户。 / p>

问题是：
如何更新User对象，而不是创建新的？

对不起，如此冗长，但是我在这里搜索不了，找不到我的问题的答案。

BTW，这些情况不为我工作：

• 扩展UserCreationForm以包括电子邮件，名字和姓氏


• 在django-profile 中添加字段first_name和last_name


• 如何在中创建一个UserProfile表单Django与first_name，last_name修改？

编辑：

根据建议@fceruti我刚刚添加request.method =='post'分支这个：

  form = UserForm（data = request.POST，instance = request.user）
  

解决方案

只需添加request.method =='post'branch this：

  form = UserForm（data = request.POST，instance = request.user）
  

Following works fine in shell:

>>> from django.contrib.auth.models import User
>>> user=User.objects.get(pk=1)
>>> user.first_name = u'Some'
>>> user.last_name = u'Name'
>>> user.save()
>>> user.first_name
u'Some'
>>> user.last_name
u'Name'

Then I try to do the same with forms:

# forms.py
class UserForm(forms.ModelForm):
    class Meta:
        model = User
        fields = ['first_name', 'last_name']


# views.py
def edit_names(request, template_name="registration/edit_names.html"):
    if request.method == "POST":
        form = UserForm(data=request.POST)
        if form.is_valid():
            user = form.save(commit=False)
            user.save()
            url = urlresolvers.reverse('my_account')
            return HttpResponseRedirect(url)
    else:
        form = UserForm(instance=request.user)
    page_title = _('Edit user names')
    return render_to_response(template_name, locals(),
        context_instance=RequestContext(request))

# edit_names.html
<form action="." method="post">{% csrf_token %}
    <table>
        {{ form.as_table }}
        <tr><td colspan="2">
            <input type="submit" />
        </td></tr>
    </table>
</form>

I open page in browser and see two fields First name and Last name. When I fill in the fields and submit the form I get the error:

 Exception Type:    IntegrityError
Exception Value:    column username is not unique

I also tried to add ['username'] to fields list in UserForm. If I submit the form with my username (as request.user), the form displays errormessage:

User with this Username already exists.

If I change the username to some unique name, the new user with that username is being created.

The question is: How can I update User object, not create new one?

Sorry for being so verbose, but I had hard search here and could not find the answer to my question.

BTW, these cases don't work for me:

• Extending UserCreationForm to include email, first name, and last name
• add field first_name and last_name in django-profile
• How to create a UserProfile form in Django with first_name, last_name modifications?

EDIT:

As suggested @fceruti I just added on request.method == 'post' branch this:

form = UserForm(data=request.POST, instance=request.user)

解决方案

Just add on request.method == 'post' branch this:

form = UserForm(data=request.POST, instance=request.user)

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