访问中间模型值Django [英] Access intermediary model values Django
本文介绍了访问中间模型值Django的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
class Person(models.Model):
name = models.CharField(max_length = 128)
def __unicode __(self):
return self.name
class Group(models.Model):
name = models.CharField(max_length = 128)
members = models.ManyToManyField(Person,through ='Membership')
def __unicode __(self):
return self.name
class Membership (models.Model):
person = models.ForeignKey(Person)
group = models.ForeignKey(Group)
date_joined = models.DateField()
invite_reason = models.CharField (max_length = 64)
解决方案
您需要查询您的会员资格
模型,如下所示:
memberships =会员资格。 objects.filter(person = person,group = group)
成员资格:
membership.invite_reason
或者你呢可以根据以下关系查询:
memberships = person.membership_set.filter(group = group)
会员资格:
membership.invite_reason
I have a simple question. using the example from django above. How can i get for example the invite_reason from Person on a Group ? or all joined dates to all groups from that person ? thanks.
class Person(models.Model):
name = models.CharField(max_length=128)
def __unicode__(self):
return self.name
class Group(models.Model):
name = models.CharField(max_length=128)
members = models.ManyToManyField(Person, through='Membership')
def __unicode__(self):
return self.name
class Membership(models.Model):
person = models.ForeignKey(Person)
group = models.ForeignKey(Group)
date_joined = models.DateField()
invite_reason = models.CharField(max_length=64)
解决方案
You'll need to query your Membership
model for that, like so:
memberships = Membership.objects.filter(person=person, group=group)
for membership in memberships:
membership.invite_reason
Alternately, you could query it based on the relation:
memberships = person.membership_set.filter(group=group)
for membership in memberships:
membership.invite_reason
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