如何通过django-rest-framework中的关系与ManytoManyField一起工作 [英] How to work with ManytoManyField with through relation in django-rest-framework

问题描述

基本上我有这样的模型：

Basically I have models like this:

class Playlist(models.Model):
    key = models.CharField(max_length=255,blank=True, unique=True)
    user = models.ForeignKey(User)
    title = models.CharField(max_length=200)
    pub_date = models.DateTimeField(auto_now_add=True)
    videos = models.ManyToManyField(Video, through='PlaylistVideo')

class PlaylistVideo(models.Model):
    playlist = models.ForeignKey(Playlist)
    video =    models.ForeignKey(Video)
    position = models.IntegerField()

class Video(models.Model):
    title = models.CharField(max_length=255,blank=True)
    description = models.TextField(blank=True)
    thumb =  models.URLField(blank=True)
    duration = models.IntegerField(default=0)

现在我想要一个API返回PLAYLISTS这样的...但视频应该按POSITION在
播放列表视频模型

Now I want an API to return PLAYLISTS like this... But Videos should be sorted by POSITION in PlaylistVideo Model

{
        "key": "h8x3",
        "title": "First Playlist",
        "pub_date": "2012-10-11T17:00:26Z",
        "videos": [
            {
                ....
            },
            {
                ....
            }
        ]
    },

我该怎么做？

推荐答案

您可以这样做：

class PlaylistVideoList(generics.ListCreateAPIView):
    serializer_class = PlaylistVideoSerializer
    queryset = PlaylistVideo.objects.all().order_by('position')

in serializers.py：

in serializers.py:

class PlaylistVideoSerializer(serializers.ModelSerializer):
    class Meta:
        model = PlaylistVideo

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