将两个查询集合到一个模板标签中 [英] Combining two queryset into a template tag
本文介绍了将两个查询集合到一个模板标签中的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我试图编写一个自定义模板,以便我可以获得最新的广告系列文章(应该只有一个)
这是我的模板标签:campaign_article.py
from itertools import chain
from django import template
from news.models import文章
from portfolio.models import Entry
register = template.Library()
def get_campaign():
#通过is_campaign = True
获取最新的新闻文章article = Article.objects.filter(is_campaign = True).order_by(' - pub_date')[ :1]
#获取最新的投资组合条目,其中is_campaign = True
portfolio = Portfolio_entry.objects.filter(is_campaign = True).order_by(' - pub_date')[:1]
#combine文章,并输入并显示最新的
campaign_article = list(chain(article,portfolio))[:1]
返回{'campaign_article':campaign_article}
register.tag('campaign',get_campaign)
我在我的模板中尝试过:
{%load campaign_article% }
{%for campaign_article in campaign%}
{{campaign_article.id}}
{%endfor%}
但是我没有任何输出。这是错误的方法吗?
解决方案
您将要创建 assignment_tag
,而不是通用标签。
所以你可以更新您的标签:
def get_campaign():
#你的东西
....
return campaign_article
register.assignment_tag(get_campaign,name ='campaign')
并更新模板为:
{%load campaign_article%}
{%campaign as campaign_list%} {#加载标签并创建campaign_list上下文变量#}
{%for campaign_article in campaign_list%}
{{campaign_article.id}}
{%endfor%}
I have two models news.article and portfolio.entry. Both models have a BooleanField for setting "is_campaign" to true.
Im trying to write a custom templatetag so I can get the latest campaign article (There should only be one)
Here is my templatetag: campaign_article.py
from itertools import chain
from django import template
from news.models import Article
from portfolio.models import Entry
register = template.Library()
def get_campaign():
#Get the newest news article with is_campaign=True
article = Article.objects.filter(is_campaign=True).order_by('-pub_date')[:1]
#Get the newest portfolio entry with is_campaign=True
portfolio = Portfolio_entry.objects.filter(is_campaign=True).order_by('-pub_date')[:1]
#combine article, and entry and display only the newest
campaign_article = list(chain(article, portfolio))[:1]
return {'campaign_article': campaign_article}
register.tag('campaign', get_campaign)
I have tried this in my template:
{% load campaign_article %}
{% for campaign_article in campaign %}
{{ campaign_article.id }}
{% endfor %}
But I don't get any output. Is this the wrong method ?
解决方案
You would want to create assignment_tag
rather than a generic tag.
So you can update your tag as:
def get_campaign():
#your stuff
....
return campaign_article
register.assignment_tag(get_campaign, name='campaign')
And update template as:
{% load campaign_article %}
{% campaign as campaign_list %} {# loads the tags and creates campaign_list context variable #}
{% for campaign_article in campaign_list %}
{{ campaign_article.id }}
{% endfor %}
这篇关于将两个查询集合到一个模板标签中的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文