Django - 从列表列表创建表 [英] Django - Create table from list of list

问题描述

我通过列表我的表格不是很好，所以这个问题可能很简单。 {{attributes}} 到模板，我想创建一个包含2行和多列的表。

模板： / strong>

 < div id =table> 
< table border = 0> 
 {％for attr in attributes％} 
< td> 
< th> {{attr.0}}< / th> 
 {{attr.1}} 
< / td> 
 {％endfor％} 
< / table> 
< / div> 
  

我想要 {{attr.0}} 作为标题并显示在单个行上，第二行显示 {{attr.1}} 。

解决方案

如何

 < div id =table> ; 
< table border = 0> 
< thead> 
< tr> 
 {％for attr_head in attributes.keys％} 
< th> {{attr_head}}< / th> 
 {％endfor％} 
< / tr> 
< / thead> 
< tbody> 
< tr> 
 {％for attr in attributes.values％} 
< td> {{attr}}< / td> 
 {％endfor％} 
< / tr> 
< / tbody> 
< / table> 
< / div> 
  

只需循环通过dict的键并将其呈现为 th 元素，然后循环遍历值，将它们呈现在 tbody 中。 th 和 td 是表中的列， tr

此外，您应该阅读 html表，他们不是那么难

I am not very good with table in html, so this question might be very simple to answer.

I pass the list of list {{ attributes }} to the template and I want to create a table with 2 rows and many columns.

TEMPLATE:

<div id="table">
<table border=0>
{% for attr in attributes %}
    <td>
       <th>{{ attr.0 }}</th>
        {{ attr.1 }}
    </td>
{% endfor %}
</table>
</div>

I want the {{ attr.0 }} to be the header and displayed on a single row and the {{ attr.1 }} displayed on the second row.

解决方案

How about

<div id="table">
<table border=0>
<thead>
    <tr>
    {% for attr_head in attributes.keys %}
       <th>{{ attr_head }}</th>
    {% endfor %}
    </tr>
</thead>
<tbody>
    <tr>
    {% for attr in attributes.values %}
        <td>{{ attr }}</td>
    {% endfor %}
    </tr>
</tbody>
</table>
</div>

Just loop through the dict's keys and rendering them as th elements in the table header and then loop through the values, rendering them inside the tbody. th and td are columns in the table and tr are rows.

Also, you should read up on html tables, they aren't that hard

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