从动态加载的DLL显示表单 [英] Displaying a form from a dynamically loaded DLL

问题描述

这是我以前问过的一个问题的扩展：这里。

This is an extension of a question I previously asked here.

长篇小说，我动态加载一个DLL，并使一个类型使用以下代码：

Long story short, I dynamically load a DLL and make a type out of it with the following code:

Assembly assembly = Assembly.LoadFile("C:\\test.dll");
Type type = assembly.GetType("test.dllTest");
Activator.CreateInstance(type);

从那里我可以使用类型引用几乎任何 dllTest 类中的任何内容。该类默认运行时应该提出一个表单（在这种情况下，相当空白，所以不复杂）。

From there I can use type to reference virtually anything in the dllTest class. The class by default when ran should bring up a form (in this case, fairly blank, so it's not complex).

我觉得我在这里缺少一个关键的代码行，保持窗体加载在屏幕上。

I feel like I'm missing a key line of code here that's keeping the form from loading on the screen.

dllTest.cs （在DLL内）包括：

dllTest.cs (within the DLL) consists of:

namespace test
{
    public partial class dllTest : Form
    {
        public dllTest()
        {
            InitializeComponent();
        }
    }
}

InitializeComponent（）设置表单的布局，这太长了粘贴到这里，不应该有所作为。

InitializeComponent() sets up the layout of the form, which is far too long to paste here and shouldn't make a difference.

任何想法？

推荐答案

您必须使用刚刚创建的表单做一些事情：

You have to do something with the form you've just created:

Assembly assembly = Assembly.LoadFile("C:\\test.dll");
Type type = assembly.GetType("test.dllTest");
Form form = (Form)Activator.CreateInstance(type);
form.ShowDialog(); // Or Application.Run(form)

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