比较基于版本号和其他条件的文件,并格式化输出 [英] Comparing files based on version number and some other criteria and Formatting the output
本文介绍了比较基于版本号和其他条件的文件,并格式化输出的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
function dll_compare(){
param($ path1,$ path2)
$ first = Get-ChildItem -Path $ path1 -Filter * .dll
$ second = Get-ChildItem -Path $ path2 -Filter * .dll
$ diff = Compare-Object -ReferenceObject $ first -DifferenceObject $ second -Property名称,长度,LastWriteTime,VersionInfo -PassThru |选择Name,Length,LastWriteTime,sideindicator,@ {n =path; e = {$ _。fullname}},@ {n =VersionInfo; e = {$ _ | Select-Object -ExpandProperty VersionInfo | Select- Object -Property Productversion}}
$ diff}
结果格式如下:我想要versioninfo包含该值,而不是@ {ProductVersion = 10.0.10240.16384}
名称:PhotoViewer.dll
长度:1827328
LastWriteTime:7/10/2015 4:31:20 PM
SideIndicator:< =
路径:D:\Site1\Dlls\PhotoViewer .dll
VersionInfo:@ {ProductVersion = 10.0.10240.16384}
解决方案
替换此行:
$ diff = Compare-Object -ReferenceObject $ first -DifferenceObject $ second -Property名称,Length,LastWriteTime,VersionInfo -PassThru |选择Name,Length,LastWriteTime,sideindicator,@ {n =path; e = {$ _。fullname}},@ {n =VersionInfo; e = {$ _ | Select-Object -ExpandProperty VersionInfo | Select- Object -Property Productversion}
与
$ diff = Compare-Object -ReferenceObject $ first -DifferenceObject $ second -Property名称,长度,LastWriteTime,VersionInfo -PassThru |
选择Name,Length,LastWriteTime,sideindicator,@ {n =path; e = {$ _。fullname}},@ {n =VersionInfo; e = {$ _。VersionInfo.Productversion}
I am comparing 2 files based on size, last write time and version number using Compare-object in Powershell. I am getting the results. The only problem is how to get the value of the version number from the result.
function dll_compare(){
param($path1,$path2)
$first = Get-ChildItem -Path $path1 -Filter *.dll
$second = Get-ChildItem -Path $path2 -Filter *.dll
$diff = Compare-Object -ReferenceObject $first -DifferenceObject $second -Property Name, Length, LastWriteTime, VersionInfo -PassThru | Select Name, Length, LastWriteTime, sideindicator,@{n="path";e={$_.fullname}},@{n="VersionInfo";e={$_|Select-Object -ExpandProperty VersionInfo |Select-Object -Property Productversion}}
$diff}
The result is in the following format: I want the versioninfo to contain the value, instead of "@{ProductVersion=10.0.10240.16384}"
Name : PhotoViewer.dll
Length : 1827328
LastWriteTime : 7/10/2015 4:31:20 PM
SideIndicator : <=
path : D:\Site1\Dlls\PhotoViewer.dll
VersionInfo : @{ProductVersion=10.0.10240.16384}
解决方案
Replace this line:
$diff = Compare-Object -ReferenceObject $first -DifferenceObject $second -Property Name, Length, LastWriteTime, VersionInfo -PassThru | Select Name, Length, LastWriteTime, sideindicator,@{n="path";e={$_.fullname}},@{n="VersionInfo";e={$_|Select-Object -ExpandProperty VersionInfo |Select-Object -Property Productversion}
with
$diff = Compare-Object -ReferenceObject $first -DifferenceObject $second -Property Name, Length, LastWriteTime, VersionInfo -PassThru |
Select Name, Length, LastWriteTime, sideindicator,@{n = "path"; e ={ $_.fullname }}, @{n = "VersionInfo"; e = { $_.VersionInfo.Productversion }
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