symfony2教义选择IFNULL [英] symfony2 doctrine select IFNULL
本文介绍了symfony2教义选择IFNULL的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有这个代码:
SELECT
IFNULL(s2.id,s1.id) AS effectiveID,
IFNULL(s2.status, s1.status) AS effectiveStatus,
IFNULL(s2.user_id, s1.user_id) as effectiveUser,
IFNULL(s2.likes_count, s1.likes_count) as effectiveLikesCount
FROM statuses AS s1
LEFT JOIN statuses AS s2 ON s2.id = s1.shared_from_id
WHERE s1.user_id = 4310
ORDER BY effectiveID DESC
LIMIT 15
我需要将其重写为querybuilder。这样的东西?
And i need to rewrite it to querybuilder. Something like that?
$fields = array('IFNULL(s2.id,s1.id) AS effectiveID','IFNULL(s2.status, s1.status) AS effectiveStatus', 'IFNULL(s2.user_id, s1.user_id) as effectiveUser','IFNULL(s2.likes_count, s1.likes_count) as effectiveLikesCount');
$qb=$this->_em->createQueryBuilder()
->select($fields)
->from('WallBundle:Status','s1')
->addSelect('u')
->where('s1.user = :user')
->andWhere('s1.admin_status = false')
->andWhere('s1.typ_statusu != :group')
->setParameter('user', $user)
->setParameter('group', 'group')
->leftJoin('WallBundle:Status','s2', 'WITH', 's2.id=s1.shared_from_id')
->innerJoin('s1.user', 'u')
->orderBy('s1.time', 'DESC')
->setMaxResults(15);
var_dump($query=$qb->getQuery()->getResult());die();
此错误是
[Syntax Error] line 0, col 7: Error: Expected known function, got 'IFNULL'
推荐答案
使用 COALESCE 而不是这样的IFNULL
Use COALESCE instead of IFNULL like this
$fields = array('COALESCE(s2.id,s1.id) AS effectiveID','COALESCE(s2.status, s1.status) AS effectiveStatus', 'COALESCE(s2.user_id, s1.user_id) as effectiveUser','COALESCE(s2.likes_count, s1.likes_count) as effectiveLikesCount');
COALESCE返回列表中的第一个值不为空,因此如果A为空且B为空,那么 COALESCE(A,B)
将返回B。
COALESCE return the first value not null in the list, so if A is null and B not null, then COALESCE(A,B)
will return B.
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