" usort"一个Doctrine\Common\Collections\ArrayCollection？ [英] "usort" a Doctrine\Common\Collections\ArrayCollection?

问题描述

在各种情况下，我需要根据对象中的属性对 Doctrine\Common\Collections\ArrayCollection 进行排序。没有找到一个这样做的方法，我这样做：

In various cases I need to sort a Doctrine\Common\Collections\ArrayCollection according to a property in the object. Without finding a method doing that right away, I do this:

// $collection instanceof Doctrine\Common\Collections\ArrayCollection
$array = $collection->getValues();
usort($array, function($a, $b){
    return ($a->getProperty() < $b->getProperty()) ? -1 : 1 ;
});

$collection->clear();
foreach ($array as $item) {
    $collection->add($item);
}

我认为这不是将所有内容复制到本地的最好方式PHP数组和后面。我想知道是否有更好的方法来usort一个 Doctrine\Common\Collections\ArrayCollection 。我想念任何文件？

I presume this is not the best way when you have to copy everything to native PHP array and back. I wonder if there is a better way to "usort" a Doctrine\Common\Collections\ArrayCollection. Do I miss any doc?

推荐答案

要排序现有的集合，您正在寻找 ArrayCollection :: getIterator（） 方法返回一个ArrayIterator。例如：

To sort an existing Collection you are looking for the ArrayCollection::getIterator() method which returns an ArrayIterator. example:

$iterator = $collection->getIterator();
$iterator->uasort(function ($a, $b) {
    return ($a->getPropery() < $b->getProperty()) ? -1 : 1;
});
$collection = new ArrayCollection(iterator_to_array($iterator));

最简单的方法是让存储库中的查询处理排序。

The easiest way would be letting the query in the repository handle your sorting.

想象一下，您有一个具有与实体的ManyToMany关系的SuperEntity。

Imagine you have a SuperEntity with a ManyToMany relationship with Category entities.

然后例如创建存储库方法像这样：

Then for instance creating a repository method like this:

// Vendor/YourBundle/Entity/SuperEntityRepository.php

public function findByCategoryAndOrderByName($category)
{
    return $this->createQueryBuilder('e')
        ->where('e.category = :category')
        ->setParameter('category', $category)
        ->orderBy('e.name', 'ASC')
        ->getQuery()
        ->getResult()
    ;
}

...使排序很容易。

... makes sorting pretty easy.

希望有帮助。

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