隐性加入和在哪里教义 - 怎么样? [英] Implicit joins and Where in Doctrine - how?
问题描述
我有一个ManyToMany用户和角色的关系。那就是我有用户表和实体类,角色表和实体以及连接表user_rolewidth user_id和role_id列。
I have a ManyToMany relation of Users and Roles. That is I have User table and entity class, Role table and entity and a joining table "user_role" width user_id and role_id columns.
现在,我最近试图让用户他们的角色,通过使用连接,像这样:
Now, I recently tried to get users with their roles, by using joins, like this:
$qb = $this->createQueryBuilder('u')
->join('user_role', 'ur', Join::ON, "I didn't know what to put here, nothing worked ")
无论如何,感谢这个答案我向我的两个实体类添加了正确的映射(注释),然后删除了我自己的连接,让Doctrine完成这个工作:
Anyway, thanks to this answer I added correct mapping (annotations) to my both entity classes and then removed my own join, letting Doctrine do the job:
$qb = $this->createQueryBuilder('u');
$q = $qb->getQuery();
$users = $q->getResult();
这个工作。我有一个所有用户的列表,然后我可以访问他们的角色(感谢User-> getRoles()方法)。
And this works. I have a list of all users, and then I can access their roles (thanks to User->getRoles() method).
然而,现在我只想列出只有具有某些角色的用户,例如ROLE_ADMIN,我不知道该怎么做:
However, now I want to list only users having certain roles, for example 'ROLE_ADMIN' and I have no idea how to do this:
$qb = $this->createQueryBuilder('u')
>where('what_to_put_here = :roles')
->setParameter('roles', 'what_to_put_here')
顺便说一句,SQL代码生成按照Doctrine看起来像这样:
By the way, the SQL code generated by Doctrine looks like this:
SELECT u0_.id AS id_0, u0_.username AS username_1, u0_.personal_name AS personal_name_2, u0_.password AS password_3, u0_.email AS email_4, u0_.is_active AS is_active_5 FROM user u0_
所以那里是没有JOIN。从Doctrine文档我知道这被称为懒惰负载 - 某些用户的角色将按需提取。
So there is no JOIN. From the Doctrine docs I know this is called "lazy load" - the roles of certain user will be fetched on demand.
但是,我该怎么做:
SELECT * FROM `user`
JOIN user_role on user_role.user_id = user.id
JOIN role on role.id = user_role.role_id
WHERE role.role_name = 'ROLE_ADMIN'
?
推荐答案
使用此选项:
$qb = $this->createQueryBuilder('u')
->innerJoin('u.roles', 'r')
->where('r.roleName = :roleNameParameter')
->setParameter('roleNameParameter', 'ROLE_ADMIN');
我假设您将实体中的角色名称映射为属性roleName。
I'm assuming you mapped the column role_name as property roleName in the entity.
这篇关于隐性加入和在哪里教义 - 怎么样?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!