错误：尝试使用id == grid1注册窗口小部件，但该ID已经注册 [英] Error: Tried to register widget with id==grid1but that id is already registered

问题描述

我正在开发我的个人网站

和我的网站的一部分我有一个偏见的视图，避免重复的代码...

和这个视图我有一个dojox。 grid.datagrid ...

我可以在同一页面中调用此视图两次（ruban.phtml）
问题是我点击1按钮是这个视图的吸引力（部分查看），然后我点击这个视图的吸引力的第二个按钮我有一个错误：

错误：试图注册小编与id ==网格，但该ID已经注册

并解决这个问题，我删除了jsId走的网格，我声明一个全局变量在调用视图时被初始化：


grid = dijit.getEnclosingWidget（dojo.byId（gridId1）;

// soit

grid = dijit.getEnclosingWidget（dojo.byId（gridId2）;


我试过但我总是有同样的问题：


...
onDownloadEnd：function（）{

  //更新网格的ID 
 var nodeGrid = dojo.byId（ancienIdGrid）; 
 nodeGrid.setAttribute（id，newIdGrid）; 
 varGlobalPourId = dijit.getEnclosingWidget（nodeGrid）; 
  

} ....

感谢你帮助我

解决方案

Dijit在dijit.registry中维护一个id字符串到小部件的哈希（请参阅dijit / _base / manager.js）更新DOM中的id不会影响该表，因此如果您尝试使用相同的ID创建一个小部件，那么我可以看到它将如何失败。如果您需要一个ID，那么如何为每个网格生成唯一的ID？

I am currently developing my personal website
and part of my site I have a biased view pr avoid duplication of code ...
and this view I have a dojox.grid.datagrid ...
I can call this view twice in the same page (ruban.phtml) the problem is that I click on 1 button that is the appeal of this view (partial view) and then I click the 2nd button that is the appeal of this view I have an error:
Error: Tried to register widget with id == grid but that id is already registered

and to address this problem, I removed the jsId walk the grid and I declared a global variable is initialized when calling the view:

grid = dijit.getEnclosingWidget(dojo.byId("gridId1");
// soit
grid = dijit.getEnclosingWidget(dojo.byId("gridId2");

I tried but I always with the same problem:

...... onDownloadEnd:function() {

          // Update the id of the grid
            var nodeGrid = dojo.byId("ancienIdGrid");
            nodeGrid.setAttribute("id", "newIdGrid");         
            varGlobalPourId = dijit.getEnclosingWidget(nodeGrid);

}....

thank you for helping me

解决方案

Dijit maintains a hash of id strings to widgets in dijit.registry (see dijit/_base/manager.js) Updating the id in the DOM will not affect that table, so I could see how it would fail if you try to create a widget with the same ID twice. How about just generating a unique id for each grid, if you need an id at all?

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