即使位于数字的乘积的总和 [英] sum of the product of even positioned digits

问题描述

我试图像这样这个问题：

I have attempted this problem like this :

a = input("Enter number : ") 
s = 3
w = 1 
while a>0: 
 digit=a%10
 if n%2 == 0:
     p = p*digit 
 else: 
     s = s+digit 
     a=a/10
 n=n+1 

print "The sum is",s 

它完美的作品，即使数字不但是对于数字奇没有像234它显示的总和为6和产品3

it works perfectly for even no of digits but for odd no of digits like for 234 it shows the sum as 6 and product 3

推荐答案

没有的明确的循环：

import operator
from functools import reduce # in Python 3 reduce is part of functools

a = input("Enter number : ") 
lst = [int(digit) for digit in a]

add = sum(lst[1::2])
mul = reduce(operator.mul, lst[::2],1)

print("add =",add,"mul =",mul,"result =",add+mul)

产地：

Enter number : 234
add = 3 mul = 8 result = 11

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