找到列出了常见的元素 [英] find common elements in lists

问题描述

我想写一张code，可以自动因素的前pression。例如， 如果我有两个列表[1,2,3,4]及[1,2,3,5]，则code应能找到在两个列表的公共元素，[2,3]，并结合一起在一个新的列表其余的元素，是[1,4,5]。

I'm trying to write a piece of code that can automatically factor an expression. For example, if I have two lists [1,2,3,4] and [2,3,5], the code should be able to find the common elements in the two lists, [2,3], and combine the rest of the elements together in a new list, being [1,4,5].

从这个帖子：的Python：如何找到列表路口 我看到常见的元素可以通过

From this post: Python: How to find list intersection? I see that the common elements can be found by

set([1,2,3,4]&set([2,3,5]). 

有没有一种简单的方法来检索每个列表不常见的元素，在我的例子是[1,4]和[5]

Is there an easy way to retrieve non-common elements from each list, in my example being [1,4] and [5]?

我可以继续做一个循环：

I can go ahead and do a for loop:

lists = [[1,2,3,4],[2,3,5]]
conCommon = []
common = [2,3]
for elem in lists:
    for elem in eachList:
    if elem not in common:
        nonCommon += elem

但是，这似乎是多余的，效率低下。 Python中是否提供任何方便的功能，可以做到这一点？在此先感谢！

But this seems redundant and inefficient. Does Python provide any handy function that can do that? Thanks in advance!!

推荐答案

使用对称差运算符设置 S（又名XOR运算符）：

Use the symmetric difference operator for sets (aka the XOR operator):

>>> set([1,2,3]) ^ set([3,4,5])
set([1, 2, 4, 5])

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