取消注册/删除dojo中的div标签的所有子节点 [英] unregister/delete all child nodes of a div tag in dojo

问题描述

我有一个div标签，让我们说mydivTag

它下有一个子节点，ID为childID

我想删除/取消注册/任何childID，然后重新创建具有相同ID的不同节点，childID

如何使用ID为childID的第一个对象进行删除，以便当我使用相同的ID创建新的对象时，我没有收到错误，小孩ID

谢谢

解决方案

p>

  dojo.query（＃childID，mydivTag）.orphan（）
  pre> 
 
 
然后
  dojo.create（div，{ id：childID}，mydivTag）
  
这些只是DOM API的缩写，如 removeChild 和 createElement  
 
I have a div tag, lets say "mydivTag"

It has a child node under it with an ID of "childID"

I want to delete/unregister/whatever "childID" and then recreate a different node with the same ID, "childID"

How do I achieve removal of the first object with ID "childID" so that when I make my new object with that same ID, I don't get an error about there already being a widget registered with the ID "childID"

Thanks
解决方案
have you tried something like
dojo.query("#childID", mydivTag).orphan()
then
dojo.create("div", {id: "childID"}, mydivTag)
These are just shorthand for DOM APIs like removeChild and createElement

                        
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