如何更改DOM中元素的名称？ [英] How can I change the name of an element in DOM?

问题描述

在有PHP的PHP中，我有一个DomElement对象，表示一个< identity />元素。我有一种情况需要改变它，元素名称为< person />，但保持相同的子元素和属性。

最简单的方法是更改​​DomElement的元素名称并保留其孩子和属性？

编辑：我刚刚发现了一个非常相似的问题（虽然它没有很好的答案）。

解决方案

可以使用 importNode（）复制< identity> 元素到新创建的< person> 元素

  function changeName（$ node，$ name）{
 $ newnode = $ node-> ownerDocument-> createElement（$ name）; 
 foreach（$ node-> childNodes as $ child）{
 $ child = $ node-> ownerDocument-> importNode（$ child，true）; 
 $ newnode-> appendChild（$ child，true）; 
} 
 foreach（$ node->属性为$ attrName => $ attrNode）{
 $ newnode-> setAttribute（$ attrName，$ attrNode）; 
} 
 $ newnode-> ownerDocument-> replaceChild（$ newnode，$ node）; 
 return $ newnode; 
} 
 
 $ domElement = changeName（$ domElement，'person'）; 
  

也许这样的东西可以工作，或者你可以尝试使用 cloneChild（） 。

编辑：其实，我只是意识到原来的功能会丢失节点的位置。根据thomasrutter链接的问题，应该使用 replaceChild（）。

In PHP with DOM, I have a DomElement object which represents an <identity/> element.

I have one case where I need to change this so its element name is <person/>, but keep the same child elements and attributes.

What would be the simplest way of changing an element name of a DomElement and keeping its children and attributes?

Edit: I have just found a very similar question (though it doesn't have very good answers).

解决方案

Could you use importNode() to copy the childNodes of your <identity> element to a newly created <person> element?

function changeName($node, $name) {
    $newnode = $node->ownerDocument->createElement($name);
    foreach ($node->childNodes as $child){
        $child = $node->ownerDocument->importNode($child, true);
        $newnode->appendChild($child, true);
    }
    foreach ($node->attributes as $attrName => $attrNode) {
        $newnode->setAttribute($attrName, $attrNode);
    }
    $newnode->ownerDocument->replaceChild($newnode, $node);
    return $newnode;
}

$domElement = changeName($domElement, 'person');

Perhaps something like that would work, or you could try using cloneChild().

Edit: Actually, I just realized that the original function would lose the placement of the node. As per the question thomasrutter linked to, replaceChild() should be used.

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