PHP表单从id而不是值发送值 [英] PHP Form sending value from an id instead of value

问题描述

我通常做的是一个隐藏字段的形式：

What I have typically been doing is something like this in a form with a hidden field:

   <input type="hidden" name="someName" value="someVal" />

，我已经能够获得像简单的一样的价值，如

and I have been able to get the value with something simple like

$someVar = $_REQUEST['someVal'];

但是现在我试图通过这样的东西发送DOM元素id中的所有值p>

But now I am trying to send all the values in a DOM element id by something like this

<input type="hidden" name="someNewName" id="element_id_name" />

我正在这样做？这甚至可以做到吗？还是我要走了？
如何从最后一行获取值？或者如何以正确的方式发送数据请求？

I am doing this correctly? Can this even be done? Or am I way off? How do I get the value out of the last line? Or how do I send that data to to request in a correct way?

谢谢，
Alex

Thanks, Alex

推荐答案

你不能通过ID检索php中的数据，它的名称可以用来改变

you cant not retrieve data in php via ID it works on name..so you neeed to change

<form method="POST" action="nextpage.php" name="myform" id="myform">
<input type="text" id="rout_markers"  name="rout_markers"/>
<input type="hidden" name="someNewName" id="someNewName" value="" />
<input type="submit" id="send-btn"  class="button" value="SEND NOW" onclick="submitform()" />
</form>

jQuery

jQuery

$("form").bind('submit',function(e){
  e.preventDefault();
  var hiddenData=$("input[name=rout_markers]").val();
  // or var hiddenData=jQuery('#rout_markers').val(); 
  $("input[type=hidden][name=someNewName]").val(hiddenData);  
});

on

以下方式检索数据

$ _ POST ['someNewName'];

$_POST['someNewName'];

更新

set onclick = submitform（） code>在提交按钮，并分配名称和 id 属性来形成和写这个

update

set onclick=submitform() in submit button and also assign name and id attribute to form and write this

<script type="text/javascript">
function submitform()
{
  var hiddenData = document.getElementById('rout_markers').value;
  document.getElementById('someNewName').value = hiddenData;
  document.myform.submit();
}
</script>

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