在具有相同命名的子节点的同时从XML文件检索特定元素 [英] Retrieving specific elements from XML file while having child nodes with same naming
本文介绍了在具有相同命名的子节点的同时从XML文件检索特定元素的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
< EN> Common Test< / EN>要返回的元素值或只有 DE或EN
的DEAllgemeiner Test< / DE>如果我有一个 NodeList
out of TESTSTEP
,我得到子节点,我也从 TEST
元素,但我只想从 TESTSTEP
元素中添加一个语言元素。如何使用 DOM
实现这一点? <?xml version =1.0encoding =ISO-8859-1standalone =no?>
< DSCT2C>
< TESTSTEPS APPLICATION =UGS>
< TESTSTEP ORDER_NUMBER =0>
< EN>普通测试< / EN>
< DE> Allgemeiner测试< / DE>
< TEST ORDER_NUMBER =0NEED_FUNCTION =trueFUNCTION_NAME =functionName>
< DESCRIPTION>
< DE> Hallo< / DE>
< EN> Hello< / EN>
< / DESCRIPTION>
< FILES>
< FILE> test.prt< / FILE>
< FILE> test.drw< / FILE>
< / FILES>
< / TEST>
< TEST ORDER_NUMBER =1NEED_FUNCTION =false>
< DESCRIPTION>
< DE> Hallo2< / DE>
< EN> Hello2< / EN>
< / DESCRIPTION>
< FILES>
< / FILES>
< / TEST>
< / TESTSTEP>
< / TESTSTEPS>
< / DSCT2C>
编辑:
我自己找到一个解决方案,这很简单;): / p>
public String getTestStepDescription(String langCode,Integer orderNumber)
{
NodeList list = documentTest.getElementsByTagName(XmlElements .TESTSTEP.toString()); (int i = 0; i< list.getLength(); i ++)
{
元素e =(Element)list.item(i);
if(e.getAttribute(XmlAttributes.ORDER_NUMBER.toString())。equals(orderNumber.toString()))
{
NodeList neu = e.getElementsByTagName(langCode.toUpperCase()) ;
for(int j = 0; j< neu.getLength(); j ++)
{
元素e2 =(Element)neu.item(j);
if(e2.getParentNode()。getNodeName()。equals(XmlElements.TESTSTEP.toString()))
{
return neu.item(j).getFirstChild()。getNodeValue );
}
}
}
}
返回ERROR_NO_TESTSTEP_DESC;
}
解决方案尝试此方法。 p>
public ArrayList< String> readXML(String xmlString,String elementName,
String textContent){
ArrayList< String> resultValues = new ArrayList< String>();
try {
boolean elementNameFlag = false,nodenameFlag = false;
DocumentBuilder dbFactory = DocumentBuilderFactory.newInstance()
.newDocumentBuilder();
InputSource is = new InputSource();
is.setCharacterStream(new StringReader(xmlString));
文档doc = dbFactory.parse(is);
NodeList list = doc.getElementsByTagName(*);
String rootNodeName = doc.getDocumentElement()。getNodeName();
if(elementName == rootNodeName || textContent == rootNodeName){
gl.writeWarning(elementName或nodeName不应该是根名称);
} else {
for(int i = 0; i< list.getLength(); i ++){
元素元素=(元素)列表。项目(i);
if(elementName == element.getNodeName()){
elementNameFlag = true;
}
if(textContent == element.getNodeName()){
nodenameFlag = true;
}
}
if(elementNameFlag == nodenameFlag){
doc.getDocumentElement()。normalize();
NodeList nList = doc.getElementsByTagName(elementName); (int temp = 0; temp< nList.getLength(); temp ++){
Node nNode = nList.item(temp);
if(nNode.getNodeType()== Node.ELEMENT_NODE){
元素eElement =(Element)nNode;
resultValues
.add(getTagValue(textContent,eElement));
}
}
} else {
}
}
} catch(异常e){
e.printStackTrace();
}
return resultValues;
} // readXML()
调用像
objectname.readXML(xmlString,TESTSTEP,EN)
I' am having some problems retrieving language localizations for teststep. I created the XML document down here and I want to have just <EN>Common Test</EN> <DE>Allgemeiner Test</DE>
elemnt values to be returned or just DE or EN
. If I have a NodeList
out of TESTSTEP
and I get the child nodes, I also get the language elements from the TEST
element, but I only want to have one language element from the TESTSTEP
element. How can I achieve this using DOM
?
<?xml version="1.0" encoding="ISO-8859-1" standalone="no"?>
<DSCT2C>
<TESTSTEPS APPLICATION="UGS">
<TESTSTEP ORDER_NUMBER="0">
<EN>Common Test</EN>
<DE>Allgemeiner Test</DE>
<TEST ORDER_NUMBER="0" NEED_FUNCTION="true" FUNCTION_NAME="functionName">
<DESCRIPTION>
<DE>Hallo</DE>
<EN>Hello</EN>
</DESCRIPTION>
<FILES>
<FILE>test.prt</FILE>
<FILE>test.drw</FILE>
</FILES>
</TEST>
<TEST ORDER_NUMBER="1" NEED_FUNCTION="false">
<DESCRIPTION>
<DE>Hallo2</DE>
<EN>Hello2</EN>
</DESCRIPTION>
<FILES>
</FILES>
</TEST>
</TESTSTEP>
</TESTSTEPS>
</DSCT2C>
EDIT:
I found a solution by myself and it was quite simply ;) :
public String getTestStepDescription(String langCode, Integer orderNumber)
{
NodeList list = documentTest.getElementsByTagName(XmlElements.TESTSTEP.toString());
for (int i = 0; i < list.getLength(); i++)
{
Element e = (Element) list.item(i);
if (e.getAttribute(XmlAttributes.ORDER_NUMBER.toString()).equals(orderNumber.toString()))
{
NodeList neu = e.getElementsByTagName(langCode.toUpperCase());
for(int j = 0; j < neu.getLength(); j++)
{
Element e2 = (Element) neu.item(j);
if(e2.getParentNode().getNodeName().equals(XmlElements.TESTSTEP.toString()))
{
return neu.item(j).getFirstChild().getNodeValue();
}
}
}
}
return "ERROR_NO_TESTSTEP_DESC";
}
解决方案 Try this method.
public ArrayList<String> readXML(String xmlString, String elementName,
String textContent) {
ArrayList<String> resultValues = new ArrayList<String>();
try {
boolean elementNameFlag = false, nodenameFlag = false;
DocumentBuilder dbFactory = DocumentBuilderFactory.newInstance()
.newDocumentBuilder();
InputSource is = new InputSource();
is.setCharacterStream(new StringReader(xmlString));
Document doc = dbFactory.parse(is);
NodeList list = doc.getElementsByTagName("*");
String rootNodeName = doc.getDocumentElement().getNodeName();
if (elementName == rootNodeName || textContent == rootNodeName) {
gl.writeWarning("elementName or nodeName should not be root name");
} else {
for (int i = 0; i < list.getLength(); i++) {
Element element = (Element) list.item(i);
if (elementName == element.getNodeName()) {
elementNameFlag = true;
}
if (textContent == element.getNodeName()) {
nodenameFlag = true;
}
}
if (elementNameFlag == nodenameFlag) {
doc.getDocumentElement().normalize();
NodeList nList = doc.getElementsByTagName(elementName);
for (int temp = 0; temp < nList.getLength(); temp++) {
Node nNode = nList.item(temp);
if (nNode.getNodeType() == Node.ELEMENT_NODE) {
Element eElement = (Element) nNode;
resultValues
.add(getTagValue(textContent, eElement));
}
}
} else {
}
}
} catch (Exception e) {
e.printStackTrace();
}
return resultValues;
}// readXML()
call like
objectname.readXML(xmlString,"TESTSTEP","EN")
这篇关于在具有相同命名的子节点的同时从XML文件检索特定元素的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文