长/内分裂意外的结果 [英] Unexpected result in long/int division
问题描述
我有这样的价值:
long millis = 11400000;
int consta = 86400000;
double res = millis/consta;
问题是:为什么 res
code> 0.0 (而不是ca. 0.131944
)?它存储在 double
中,所以应该没有四舍五入?
The question is: why res
equals 0.0
(instead of ca. 0.131944
)? It's stored in double
so there should be no rounding right?
推荐答案
当您使用二进制运算符时,两个参数应该是相同的类型,结果也将在它们的类型中。当你想划分(int)/(long)
,它变成(long)/(long)
结果是(long)
。你应该使用(double)/(long)
或(int)/(double)
获得双重结果。由于double大于int和long,int和long将在(double)/(long)
和(int)/(双)
When you are using a binary operator, both arguments should be of a same type and the result will be in their type too. When you want to divide (int)/(long)
it turns into (long)/(long)
and the result is (long)
. you shouldmake it (double)/(long)
or (int)/(double)
to get a double result. Since double is greater that int and long, int and long will be turned into double in (double)/(long)
and (int)/(double)
这篇关于长/内分裂意外的结果的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!