在java中将两个整数分成两个 [英] Dividing two integers to a double in java

问题描述

我可以看到这是新程序员的常见问题，但是我没有成功地实现我的代码的任何解决方案。基本上我想划分w和v，它必须保存到一个double变量中。但是它打印[0.0，0.0，...，0.0]

I can see this is a common problem for new programmers, however I didn't succeed in implementing any of the solution to my code. Basically I want to divide w and v, which must be saved to a double variable. But it prints [0.0, 0.0, ... , 0.0]

public static double density(int[] w, int[] v){
double d = 0;
    for(L = 0; L < w.length; L++){
        d = w[L]  /v[L];
    }
    return d;
}

推荐答案

这行这里 d = w [L] / v [L]; 发生在几个步骤

This line here d = w[L] /v[L]; takes place over several steps

d = (int)w[L]  / (int)v[L]
d=(int)(w[L]/v[L])            //the integer result is calculated
d=(double)(int)(w[L]/v[L])    //the integer result is cast to double

$ b $换句话说，精确度已经在你转换成双倍之前就已经消失了，所以你需要先转一次，所以

In other words the precision is already gone before you cast to double, you need to cast to double first, so

d = ((double)w[L])  / (int)v[L];

这将强制java使用双重数学，而不是使用整数数学，然后转换为双精度在结尾

This forces java to use double maths the whole way through rather than use integer maths and then cast to double at the end

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