PHP从数据库中下载数据 [英] PHP Drop Down Data from Database

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本文介绍了PHP从数据库中下载数据的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在根据我的数据库为数据设置 select field 。所以,基本上,我想让它为我的数据库中的所有用户下拉菜单。所以喜欢而不是做:

I am trying to make an select field for data according to my database. So, basically, I want it to have a dropdown menu for all the users in my database. So like instead of doing:

<select>
  <option>1st User in Db</option>
  <option>2nd User in Db</option>
</select>

它只是自动显示所有。

我尝试获取$ row ['uname'],并将其设置为$ user,但是在下拉列表中仅显示MY用户。

I tried fetching a $row['uname'], and setting it as $user, but then it only shows MY user in the dropdown.

示例: http://prntscr.com/dwksy

它只显示我的帐户,而不是所有其他帐户。有谁知道该怎么做?谢谢!

It only shows my account, admin, instead of all the other ones. Anyone know how to do this? Thanks!

推荐答案

<?php

session_start();
include 'config.php';
$user = $_SESSION['username'];
$qry=("SELECT `rank`, `uname` FROM users WHERE uname='$user'");
$result=mysql_query($qry);
$row = mysql_fetch_assoc($result);
$rank = $row["rank"]

if ($_SESSION['loggedin'] == true) {
    if ($rank >= 3) {
        $qry=("SELECT `rank`, `uname` FROM users");
        $result=mysql_query($qry);

        echo "
        <form action='' method='POST'>
        <select>";

        while ($row = mysql_fetch_assoc($result)) {
            $rank = $row['rank'];
            $users = $row['uname'];
            $lol = ucwords($users);

            echo "<option>$lol</option>";
        }

        echo "</select>
        </form>
        ";
      } else {
          echo "Your level is not 3, but you are logged in.";
      }
  } else {
     echo "Please login.";
  }

这篇关于PHP从数据库中下载数据的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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