显示没有页面模板的Drupal视图 [英] displaying a Drupal view without a page template around it

问题描述

我想显示一个Drupal视图，而没有通常包围它的页面模板 - 我只想要查看节点的纯HTML内容。

I would like to display a Drupal view without the page template that normally surrounds it - I want just the plain HTML content of the view's nodes.

这个视图将被包含在另一个非Drupal网站中。

This view would be included in another, non-Drupal site.

我希望通过一些视图来做到这一点，所以我可以快速轻松地设置这个解决方案将是最好的 - 我不希望每次需要在某个地方添加视图时创建一个.tpl.php文件。

I expect to have to do this with a number of views, so a solution that lets me set these up rapidly and easily would be the best - I'd prefer not to have to create a .tpl.php file every time I need to include a view somewhere.

推荐答案

我正在寻找一种通过ajax提取节点数据的方法，并为Drupal 6提供了以下解决方案。在实现以下更改后，如果在URL中添加ajax = 1（例如mysite.com/node / 1？ajax = 1），您将只得到内容，无需页面布局。

I was looking for a way to pull node data via ajax and came up with the following solution for Drupal 6. After implementing the changes below, if you add ajax=1 in the URL (e.g. mysite.com/node/1?ajax=1), you'll get just the content and no page layout.

在您的主题的template.php文件中：

in the template.php file for your theme:

function phptemplate_preprocess_page(&$vars) {

  if ( isset($_GET['ajax']) && $_GET['ajax'] == 1 ) {
        $vars['template_file'] = 'page-ajax';
  }

}

然后创建page-ajax.tpl .php在您的主题目录中，内容如下：

then create page-ajax.tpl.php in your theme directory with this content:

<?php print $content; ?>

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