Drupal - 根据节点的分类术语ID显示块 [英] Drupal - display blocks according to node's taxonomy term ID
问题描述
我只是试图将块的可见性限制在具有一定分类标识的节点上。我正在使用这个片段...:
<?php
$ term_id_to_trigger_show_block = 109;
if((arg(0)=='node')&& is_numeric(arg(1))){
$ terms = taxonomy_node_get_terms(arg(1));
foreach($ terms as $ term){
if($ term-> tid == $ term_id_to_trigger_show_block){
return TRUE;
}
}
}
?>
...但我没有快乐,该块仍然隐藏在相关节点上。 >
任何想法?
干杯
看起来像drupal6 taxonomy_node_get_tree()需要一个节点而不是nid。
更改代码的最简单方法是:
<?php
$ term_id_to_trigger_show_block = 109;
if((arg(0)=='node')&& is_numeric(arg(1))){
$ node = node_load(arg(1));
$ terms = taxonomy_node_get_terms($ node);
foreach($ terms as $ term){
if($ term-> tid == $ term_id_to_trigger_show_block){
return TRUE;
}
}
}
?>
node_load()缓存内存中的节点,所以它不会是一个很大的性能命中。
但请等待!你可能可以进一步改进...
menu_get_item()将在加载节点对象时获取当前加载的菜单项,它将调用taxonomy_node_get_terms()。所以你可以简化为:
<?php
$ term_id_to_trigger_show_block = 109;
$ object = get_menu_item();
if(isset($ object-> taxonomy)){
foreach($ object-> taxonomy as $ term){
if($ term-> tid == $ term_id_to_trigger_show_block){
return TRUE;
}
}
}
?>
这将获得具有分类对象的其他对象类型,这可能会导致一些混乱,如果这样坚持 arg(0)=='node'
back in。
I'm just trying to restrict block visibility to nodes that have a certain taxonomy ID. I'm using this snippet...:
<?php
$term_id_to_trigger_show_block = 109;
if ((arg(0) == 'node') && is_numeric(arg(1))) {
$terms = taxonomy_node_get_terms(arg(1));
foreach($terms as $term) {
if ($term->tid == $term_id_to_trigger_show_block) {
return TRUE;
}
}
}
?>
...but I get no joy, the block remains hidden on the relevant nodes.
Any ideas?
Cheers
It looks like in drupal6 taxonomy_node_get_tree() takes a node rather than a nid.
The easiest way to change your code is:
<?php
$term_id_to_trigger_show_block = 109;
if ((arg(0) == 'node') && is_numeric(arg(1))) {
$node = node_load(arg(1));
$terms = taxonomy_node_get_terms($node);
foreach($terms as $term) {
if ($term->tid == $term_id_to_trigger_show_block) {
return TRUE;
}
}
}
?>
node_load() caches nodes in memory so it won't be a big performance hit.
But wait! you may be able to refine this even further...
menu_get_item() will get the currently loaded menu item when the node object is loaded it will call taxonomy_node_get_terms(). So you can simplify to:
<?php
$term_id_to_trigger_show_block = 109;
$object = get_menu_item();
if (isset($object->taxonomy)) {
foreach($object->taxonomy as $term) {
if ($term->tid == $term_id_to_trigger_show_block) {
return TRUE;
}
}
}
?>
This will get other object types wich have a taxonomy object which could cause some confusion, if so stick the arg(0) == 'node'
back in.
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